Answer:
It's a very good subject!
The complete question is as follows: Barium chloride (BaCl2) emits a green color when flame tested. What can be said about the wavelength of light it emits? Select all that apply.
A) The thermal energy is transferred to the outer electrons of the barium ions.
B) The electrons gain enough energy to excite them to a higher energy level.
C) The electrons drop back down to their ground state, gaining energy.
D) The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Answer: The following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Explanation:
As barium chloride is emitting green color when flame tested. This means that thermal energy is being transferred to the outer electrons of barium ions.
A visible light is emitted by a substance when its electrons move from a region of higher energy level to lower energy level. This is because energy is given off by the electrons when they move in a lower region.
This is only possible when the electrons gain enough energy to excite them to a higher energy level.
Also, the electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Thus, we can conclude that following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Matter can only me transformed, but not created or destroyed.
1 ) Cobalt(II) nitrate react with nitrate zinc(II) to produce cobalt(III)-zinc oxide, nitrogen dioxide and oxygen
2Co(NO3)2 + Zn(NO3)2 → Co2ZnO4 + 6NO2 + O2
2) Calcium hydroxide react with phosphoric acid to produce calcium, hydrogen phosphate and water
Ca(OH)2 + H3PO4 → CaHPO4 + 2H2O
3) Copper(II) dichromate will react with Iron(III) arsenate to form Copper(II) Arsenate and Iron(III) dichromate
3Cr2CuO7 + 2AsFeO4 → Cu3(AsO4)2 + Fe2(Cr2O7)3
Reaction Type
: Double Displacement
4) aluminium hydroxide and hydrochloric acid react to form aluminium chloride and water
Al(OH)3 + 3HCl → AlCl3 + 3H2O
Answer:
Explanation:
<em>0.5 i go to k12 i jus took the test</em>
