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BabaBlast [244]
3 years ago
14

After severe dust storms in the 1930s, practices were put in place to reduce soil erosion. Which

Chemistry
2 answers:
timurjin [86]3 years ago
5 0

Answer: Farmers were paid to practice soil-conserving techniques like crop rotation and terracing

Explanation:

read about it here: https://www.pbs.org/wgbh/americanexperience/features/dust-bowl-surviving-dust-bowl/

kramer3 years ago
3 0

Answer:

keep the soil wet

Explanation: if the song wet it will not cause as much dust storms

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the mass of a 125 cm3 piece of material is 82.75 g. determine the density of this material . please explain
andre [41]
You would do 82.75 divided by 125 cm3 and get 0.6620 g/cm3 because to find density you mist divide mass and volume and grams is always mass and cm3 or mL is always volume. hope i helped!
6 0
4 years ago
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
Sloan [31]

Answer:

Mass =  42.8g

Explanation:

4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol

Oxygen = 63.4g × 1mol / 32g = 1.9813mol

Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.

Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.

5 moles of O2  = 6 moles of H2O

1.9831 moles = x

x = (1.9831 * 6 ) / 5

x = 2.37972 moles

Mass of H2O = Molar mass * Molar mass

Mass = 2.7972 * 18

Mass =  42.8g

6 0
3 years ago
Given the information you now know, what is the effect of hyperventilation on blood pH?pH? During hyperventilation, the rapid in
Ksju [112]

Answer:

When hypercapnia processes occur, where the concentration of carbon dioxide gas increases in the blood, the protonization of the blood increases, this means that the H + ions increase in concentration, thus generating metabolic acidosis.

This metabolic acidosis is regulated by various systems, but the respiratory system collaborates by generating hyperventilation, to increase blood oxygen pressures, decrease CO2 emissions, and indirectly decrease acidity.

Explanation:

This method of regulating the body is crucial, since the proteins in our body will not be altered if they do not happen.

The enzymes, the red globules, and many more fundamental things for life ARE PROTEINS, that in front of acidic media these modify their structure by denaturing themselves and ceasing to fulfill their functions. This is the reason why it seeks to neutralize the blood pH when it comes to an increase in CO2.

3 0
3 years ago
2. Stronger intermolecular forces =______ boiling point​
Leto [7]

Stronger intermolecular forces = higher boiling point​

The stronger the intermolecular forces, the harder the molecules are to pull/break apart, which means a higher boiling point.

5 0
3 years ago
Write the balanced COMPLETE ionic equation for the reaction when aqueous BaCl₂ and aqueous (NH₄)₂SO₄ are mixed in solution to fo
Vinvika [58]

Answer:

Ba²⁺(aq) + 2 Cl⁻(aq) + 2 NH₄⁺(aq) + SO₄²⁻(aq) ⇒ 2 NH₄⁺(aq) + 2 Cl⁻(aq) + BaSO₄(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous BaCl₂ and aqueous (NH₄)₂SO₄ are mixed in solution to form aqueous NH₄Cl and solid BaSO₄. This is a double displacement reaction.

BaCl₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄Cl(aq) + BaSO₄(s)

The complete ionic equation includes all the ions and insoluble species.

Ba²⁺(aq) + 2 Cl⁻(aq) + 2 NH₄⁺(aq) + SO₄²⁻(aq) ⇒ 2 NH₄⁺(aq) + 2 Cl⁻(aq) + BaSO₄(s)

4 0
3 years ago
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