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FromTheMoon [43]
3 years ago
7

How do the cells in your body get energy?

Chemistry
1 answer:
Anastasy [175]3 years ago
4 0
The cells get into your body by the lungs this answer is correct cause i had the same question and my teacher mark it correct
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7. Although carbon's three isotopes are carbon-12, carbon-13, and carbon-14, its
Naddik [55]

Answer:

B

Explanation:

carbon 12 is most useful to humans

4 0
3 years ago
How are priorities assigned to each group bonded to a tetrahedral stereogenic center?
inn [45]

To assign a priority to an atom that is part of multiple bonds, treat the multiple bonds as an equivalent number of single bonds. Hence, option A is correct.

<h3>What is a stereogenic centre?</h3>

A carbon atom is a chiral (stereogenic) centre if it is tetrahedral (sp3) and has four different groups (ligands) attached to it.

To assign a priority to an atom that is part of multiple bonds, treat the multiply bonded atom as an equivalent number of singly bonded atoms.

If two isotopes are bonded to the stereogenic centre, the isotope with the higher mass number has a higher priority.

Hence, option A is correct.

Learn more about the stereogenic centre here:

brainly.com/question/12995502

#SPJ1

8 0
2 years ago
how many moles of carbon monoxide can be produced from 8 moles of carbon if carbon is the limiting reagent?
Mademuasel [1]

Answer:

8 moles of CO

Explanation:

To produce carbon monoxide we begin from C and O₂ as this reaction shows:

2C + O₂ → 2CO

Therefore, 2 moles of C can produce 2 moles of CO

If I have 8 moles of C, I must produce 8 moles of CO

Ratio is 1:1

6 0
3 years ago
For a given reaction, ΔS = +106 J/mol ⋅ K, and the reaction is spontaneous at temperatures above the crossover temperature, 446
solniwko [45]

Answer:  47.276 kJ/mol

Explanation:

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change

\Delta S = entropy change  = +106 J/mol

T = temperature in Kelvin  = 446 K

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

\Delta H=T\Delta S

\Delta H=T\Delta S

\Delta H=446K\times +106J/Kmol=47276J/mol=47.276kJ/mol   (1kJ=1000J)

Thus the value of ΔH = 47.276 kJ/mol, assuming that ΔH and ΔS do not vary with temperature.

7 0
3 years ago
What is the equilibrium associated with ka3 for h3po4?
Vlad [161]
Phosphoric acid has 3 pKa values (pKa1=2.1,  pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values: 

H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq)         pKₐ₁ 
<span>

</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq)       pKₐ₂


HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq)          pKₐ₃ 

The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
4 0
4 years ago
Read 2 more answers
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