Answer:
v₀ = 13.9 10³ m / s
Explanation:
Let's analyze this exercise we can use the basic kinematics relationships to love the initial velocity and the acceleration we can look for from Newton's second law where force is gravitational attraction.
F = m a
G m M / x² = m dv / dt = m dv/dx dx/dt
G M / x² = dv/dx v
GM dx / x² = v dv
We integrate
v² / 2 = GM (-1 / x)
We evaluate between the lower limits where x = Re = 6.37 10⁶m and the velocity v = vo and the upper limit x = 2.50 10⁸m with a velocity of v = 8.50 10³ m/s
½ ((8.5 10³)² - v₀²) = GM (-1 /(2.50 10⁸) + 1 / (6.37 10⁶))
72.25 10⁶ - v₀² = 2 G M (+0.4 10⁻⁸ - 1.57 10⁻⁷)
72.25 10⁶ - v₀² = 2 6.63 10⁻¹¹ 5.98 10²⁴ (-15.3 10⁻⁸)
72.25 10⁶ - v₀² = -1.213 10⁸
v₀² = 72.25 10⁶ + 1,213 10⁸
v₀² = 193.6 10⁶
v₀ = 13.9 10³ m / s
As per Newton's III law we can say that
Force applied by object 1 on object 2 is always equal in magnitude and opposite in direction of the force that object 2 apply on object 1.
So we can say it as
now here above question is based upon the same
if a bag of vegetables applied a force F = 22.5 N of the surface stand the the same surface will apply same magnitude of force in opposite direction on the vegetables bag
So our answer will be F = 22.5 N (upwards).
Answer:
D.
R increases
V is constant
I decreases
Explanation:
The resistance of a wire is given by the following formula:
It is clear from this formula that resistance is directly proportional to the length of wire. So, when length of wire is increased, <u>the resistance of circuit increases</u>.
The <u>voltage in the circuit will be constant</u> as the voltage source remains same and it is not changed.
Now, we can use Ohm Law:
V = IR
at constant V:
I ∝ 1/R
it means that current is inversely proportional to resistance. Hence, the increase of resistance causes <u>the current in circuit to decrease.</u>
Therefore, the correct option will be:
<u>D.</u>
<u>R increases
</u>
<u>V is constant
</u>
<u>I decreases</u>
Answer:
An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. ... A net force = unbalanced force. If however, the forces are balanced (in equilibrium) and there is no net force, the object will not accelerate and the velocity will remain constant.
Explanation:
Explanation:
<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>
<em>Energy</em><em> </em><em>is</em><em> </em><em>defined</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>capacity</em><em> </em><em>or</em><em> </em><em>ability</em><em> </em><em>to</em><em> </em><em>do</em><em> </em><em>work</em><em>.</em><em> </em><em>It's</em><em> </em><em>SI</em><em> </em><em>unit</em><em> </em><em>is</em><em> </em><em>Joule</em><em>.</em>
<em>here</em><em>,</em>
<em>Joule</em><em> </em><em>=</em><em> </em><em>(</em><em>kg</em><em>×</em><em>m</em><em>×</em><em>m</em><em>)</em><em>/</em><em>(</em><em>s</em><em>×</em><em>s</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>kg</em><em>×</em><em>m</em><em>^</em><em>2</em><em>/</em><em>s</em><em>^</em><em>2</em><em>.</em>
<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>derived</em><em> </em><em>unit</em><em> </em><em>is</em><em> </em><em>kg</em><em>.</em><em>m</em><em>^</em><em>2</em><em> </em><em>by</em><em> </em><em>s</em><em>^</em><em>2</em><em>.</em>
<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>
