A number, one fourth of that number, and 1/5 of that number are added. The result is 58. What is the original number?
2 answers:
So we have a number, x, one fourth of the number (x/4) and a fifth of that number (x/5). We use x for all of them bc it is the same number. The first thing we will do is fine a common denominator which is 20. To get 20 we multiply a fourth by 5, a fifth by 4, simply x by 20 and 58 by 20. Once we have the denominators we can eliminate them so we cross them out and we are left with a normal equation in which we solve for x, as seen in the picture. I hope I helped. If you have any questions please x. You might want to check out the picture to understand it better.
- Laura B.
- Laura B.
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