A number, one fourth of that number, and 1/5 of that number are added. The result is 58. What is the original number?
2 answers:
So we have a number, x, one fourth of the number (x/4) and a fifth of that number (x/5). We use x for all of them bc it is the same number. The first thing we will do is fine a common denominator which is 20. To get 20 we multiply a fourth by 5, a fifth by 4, simply x by 20 and 58 by 20. Once we have the denominators we can eliminate them so we cross them out and we are left with a normal equation in which we solve for x, as seen in the picture. I hope I helped. If you have any questions please x. You might want to check out the picture to understand it better.
- Laura B.
- Laura B.
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Given:
Total number of marbles in the bag = 150
There are 21 blue marbles for every 4 white marbles.
To find:
The number of blue marbles in the bag.
Solution:
Since, there are 21 blue marbles for every 4 white marbles, therefore the ratio of blue marble to white marbles is 21:4.
Let the number of blue marbles be 21x and white marbles be 4x.
Total number of marbles in the bag = 150
Divide both sides by 25.
Now,
Therefore, the number of blue marbles is 126.
9514 1404 393
Answer:
(0, π/4] ∪ (π, 5π/4]
Step-by-step explanation:
Multiplying by 2 gives ...
cot(x) ≥ 1
The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.
x ∈ (0, π/4] ∪ (π, 5π/4]
_____
(a, b] is interval notation for a < x ≤ b
