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DedPeter [7]
3 years ago
10

how many grams of carbon tetrachloride can be produced from reacting 709.0 grams of chlorine (CI2) with excess methane?

Chemistry
1 answer:
bearhunter [10]3 years ago
8 0
384.5 grams
Hope this helps!
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Please help me I have not gone over this in like 8 months and can not remember how to do it
Leona [35]

Answer:

91%

Explanation:

Since you are just trying to find the yield, take the moles of the substance from the products and divide it by the mol value of the reactants. Multiply by 100 to find percentage

0.45 ÷ 0.41 = 0.91111...

91%

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2 years ago
The CH3 ion is a conjugate base of CH4 and CH4 shows no evidence of being an acid in water. What happens when CH3 ion is added t
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Whenever fa body object is in motion there is always ____ to oppose the motion
insens350 [35]
Friction. Imagine rubbing your hand against a carpet and how it gets hot even though you are pushing it afar. That is friction.
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How are gas giants different from each other
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Answer:there different from the rocky like planets gas giants don't have such a firm surface like rocky terrestrial planets

Explanation:

5 0
2 years ago
The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 5.13 g sam
storchak [24]

Answer:

20.66 % of the ore is antimony

Explanation:

Step 1: Data given

Mass of stibnite (Sb2S3) = 5.13 grams

The Sb3+(aq) is completely oxidized by 27.7 mL of a  0.105 M aqueous solution of KBrO3(aq).

Step 2: The balanced equation

BrO3-(aq)+ 3Sb^3+(aq) + 6 H+ → Br-(aq) + 3Sb^5+(aq) + 3H2O (l)

Step 3: Calculate moles KBrO3

Moles KBrO3 = molarity * volume

Moles KBrO3 = 0.105 M *0.0277 L

Moles KBrO3 = 0.0029085 moles

Step 4: Calculate moles Bro3-

in 1 mol KBrO3 we have 1 mol K+ and 1 mol BrO3-

In 0.0029085 moles KBrO3 we have 0.0029085 moles BrO3-

Step 5: Calculate moles Sb

For 1 mol BrO3- we need 3 mol Sb^3+ to produce 1 mol Br- and 3 mol Sb^5+

For 0.029085 moles BrO3- we need 3*0.0029085 = 0.0087255 moles Sb

Step 6: Calculate mass Sb

Mass Sb = moles Sb * molar mass Sb

Mass Sb = 0.0087255 moles * 121.76 g/mol

Mass Sb = 1.06 grams

Step 7: Calculate the percentage of Sb in the ore

% Sb = (mass Sb / total mass) * 100%

% Sb = (1.06 grams / 5.13 grams) * 100 %

% Sb = 20.66 %

20.66 % of the ore is antimony

8 0
3 years ago
Read 2 more answers
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