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Ivenika [448]
2 years ago
12

Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number

c) Peclet number d) Stanton
Chemistry
1 answer:
Cloud [144]2 years ago
5 0

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.

P_r = \frac{\nu}{\alpha}

Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.

S_c= \frac{\nu}{\nu_{AB}}

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The table lists properties of a few known elements, but the states of matter and melting points are missing. Look up the element
kolbaska11 [484]

The properties of the given elements are as follows:

Potassium, K;

  • State of matter: Solid
  • Melting point: 63.5 °C
  • Conductivity: Good
  • Solubility (H2O): reacts rapidly with water

Iodine, I;

  • State of matter: solid
  • Melting point: 113.5 °C
  • Conductivity: very poor
  • Solubility (H2O): negligible

Gold, Au;

  • State of matter: solid
  • Melting point: 1064 °C
  • Conductivity: excellent
  • Solubility (H2O): none

Germanium, Ge;

  • State of matter: solid
  • Melting point: 938.2 °C
  • Conductivity: fair
  • Solubility (H2O): none

Barium, Ba;

  • State of matter: solid
  • Melting point: 727 °C
  • Conductivity: good
  • Solubility (H2O): reacts strongly

Argon, Ar;

  • State of matter: gas
  • Melting point: -189.4 °C
  • Conductivity: none
  • Solubility (H2O): negligible

Chlorine Cl;

  • State of matter: gas
  • Melting point: -101.5 °C
  • Conductivity: poor
  • Solubility (H2O): slight

Rubidium, Rb;

  • State of matter: solid
  • Melting point: 39.48 °C
  • Conductivity: good
  • Solubility (H2O): reacts violently

Silver, Ag;

  • State of matter: solid
  • Melting point: 961.8 °C
  • Conductivity: excellent
  • Solubility (H2O): none

Calcium, Ca;

  • State of matter: solid
  • Melting point: 842 °C
  • Conductivity: good
  • Solubility (H2O): reacts

Silicon, Si;

  • State of matter: solid
  • Melting point: 1,410 °C
  • Conductivity: intermediate
  • Solubility (H2O): none

Xenon, Xe;

  • State of matter: gas
  • Melting point: -111.8 °C
  • Conductivity: very poor
  • Solubility (H2O): none

<h3>What are elements?</h3>

Elements are pure substances which are composed of similar atoms.

Elements are defined as substances which cannot be split into simpler substances by an ordinary chemical process.

Elements have different physical and chemical properties and can be classified into:

  • metals
  • semi-metals
  • non-metals

In conclusion, the physical and chemical properties of the elements vary from metals to non-metals.

Learn more about elements at: brainly.com/question/6258301

#SPJ1

7 0
1 year ago
13. Due to changes in energy, substances can change their state of matter. When
AlexFokin [52]
When’s I would like to say that it may be B because
3 0
3 years ago
A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylin
polet [3.4K]

Answer:

12.09 L

Explanation:

Step 1: Convert 826.1 mmHg to atm

We will use the conversion factor 760 mmHg = 1 atm.

826.1 mmHg × 1 atm/760 mmHg = 1.087 atm

Step 2: Convert 427.8 J to L.atm

We will use the conversion factor 101.3 J = 1 L.atm.

427.8 J × 1 L.atm/101.3 J = 4.223 L.atm

Step 3: Calculate the change in the volume

Assuming the work done (w) is 4.223 L.atm against a pressure (P) of 1.087 atm, the change in the volume is:

w = P × ΔV

ΔV = w/P

ΔV = 4.223 L.atm/1.087 atm = 3.885 L

Step 4: Calculate the final volume

V₂ = V₁ + ΔV

V₂ = 8.20 L + 3.885 L = 12.09 L

5 0
2 years ago
Which of the following is NOT the same?
Inessa [10]

All are the same. It equals to the same thing.

4 0
2 years ago
Read 2 more answers
What was Ernest Rutherford's experiment?
Dafna1 [17]

Answer:

C. He shot tiny alpha particles through a piece of gold foil.

Explanation:

In the year 1911, Ernest Rutherford performed the gold foil experiment which gave a deeper perspective to the structure of an atom.

He simply collided a thin gold foil with an alpha particle which he generated from a radioactive source. He discovered that most of the alpha particles passed through the thin gold foil but a few were deflected back. His discovery led to the proposition of the nuclear model of the atom.

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3 years ago
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