The properties of the given elements are as follows:
Potassium, K;
- State of matter: Solid
- Melting point: 63.5 °C
- Conductivity: Good
- Solubility (H2O): reacts rapidly with water
Iodine, I;
- State of matter: solid
- Melting point: 113.5 °C
- Conductivity: very poor
- Solubility (H2O): negligible
Gold, Au;
- State of matter: solid
- Melting point: 1064 °C
- Conductivity: excellent
- Solubility (H2O): none
Germanium, Ge;
- State of matter: solid
- Melting point: 938.2 °C
- Conductivity: fair
- Solubility (H2O): none
Barium, Ba;
- State of matter: solid
- Melting point: 727 °C
- Conductivity: good
- Solubility (H2O): reacts strongly
Argon, Ar;
- State of matter: gas
- Melting point: -189.4 °C
- Conductivity: none
- Solubility (H2O): negligible
Chlorine Cl;
- State of matter: gas
- Melting point: -101.5 °C
- Conductivity: poor
- Solubility (H2O): slight
Rubidium, Rb;
- State of matter: solid
- Melting point: 39.48 °C
- Conductivity: good
- Solubility (H2O): reacts violently
Silver, Ag;
- State of matter: solid
- Melting point: 961.8 °C
- Conductivity: excellent
- Solubility (H2O): none
Calcium, Ca;
- State of matter: solid
- Melting point: 842 °C
- Conductivity: good
- Solubility (H2O): reacts
Silicon, Si;
- State of matter: solid
- Melting point: 1,410 °C
- Conductivity: intermediate
- Solubility (H2O): none
Xenon, Xe;
- State of matter: gas
- Melting point: -111.8 °C
- Conductivity: very poor
- Solubility (H2O): none
<h3>What are elements?</h3>
Elements are pure substances which are composed of similar atoms.
Elements are defined as substances which cannot be split into simpler substances by an ordinary chemical process.
Elements have different physical and chemical properties and can be classified into:
- metals
- semi-metals
- non-metals
In conclusion, the physical and chemical properties of the elements vary from metals to non-metals.
Learn more about elements at: brainly.com/question/6258301
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When’s I would like to say that it may be B because
Answer:
12.09 L
Explanation:
Step 1: Convert 826.1 mmHg to atm
We will use the conversion factor 760 mmHg = 1 atm.
826.1 mmHg × 1 atm/760 mmHg = 1.087 atm
Step 2: Convert 427.8 J to L.atm
We will use the conversion factor 101.3 J = 1 L.atm.
427.8 J × 1 L.atm/101.3 J = 4.223 L.atm
Step 3: Calculate the change in the volume
Assuming the work done (w) is 4.223 L.atm against a pressure (P) of 1.087 atm, the change in the volume is:
w = P × ΔV
ΔV = w/P
ΔV = 4.223 L.atm/1.087 atm = 3.885 L
Step 4: Calculate the final volume
V₂ = V₁ + ΔV
V₂ = 8.20 L + 3.885 L = 12.09 L
All are the same. It equals to the same thing.
Answer:
C. He shot tiny alpha particles through a piece of gold foil.
Explanation:
In the year 1911, Ernest Rutherford performed the gold foil experiment which gave a deeper perspective to the structure of an atom.
He simply collided a thin gold foil with an alpha particle which he generated from a radioactive source. He discovered that most of the alpha particles passed through the thin gold foil but a few were deflected back. His discovery led to the proposition of the nuclear model of the atom.