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Natasha_Volkova [10]
3 years ago
14

Help me please will mark brainliest ​

Chemistry
2 answers:
Ilya [14]3 years ago
4 0

Answer:

D

Explanation:

Period is horizontal group, so left to right it does increase. Down the side they are numbered 1-7 and depending on valence electrons they can have different properties

murzikaleks [220]3 years ago
4 0

Answer:

A

Explanation:

Im pretty sure it's A. I MIGHT be wrong so dont quote me on this. THis is what the internet says:

"Atomic Radius. Atomic radii decrease from left to right across a period and increase from top to bottom along a group."

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In a sample of H2SO4 containing 200 sulfur (S) atoms, how many atoms of hydrogen (H) would there be?
Otrada [13]

In a sample of H2SO4 that contain 200 S atom the number of hydrogen atoms  would be 400  atoms

explanation

there are two moles of H2  in H2SO4 therefore by use of ratio between S:H2 which is 1:2 atoms therefore the atoms of hydrogen = 2 x200 = 400 atoms

5 0
4 years ago
How many moles of gold are Cleveland to 1.204×1024 atoms
Whitepunk [10]

Answer:

10

Explanation:

ye

4 0
3 years ago
A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.
solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

E = \frac{h \times c }{\lambda }

where,

  • h: Planck's constant
  • c: speed of light

E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s  \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0
3 years ago
How many grams of Cl2 are consumed to produce 12.0 g of KCl?
Alla [95]

The reaction is:

Cl2 + 2 KBr --> 2 KCl + Br2

Moles of KCl is

n = m /M = 12 /74 = 0.16 mol

As, twice the moles of KCl is producing from 1 mol of chlorine

mole of Cl2 = 0.16 /2 = 0.08 mol

Mass of Cl2

m /70 = 0.08 = 5.6 g

Hence, 5.6 g mol Cl2 consumed to produce KCl

7 0
4 years ago
A 63 kg object needs to be lifted 7 meters in a matter of 5 seconds. Approximately how much horsepower is required to achieve th
Digiron [165]
A. is the correct answer!
7 0
3 years ago
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