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2 years ago

Which statements about the structure of the periodic table are true?

Chemistry

1 answer:

DiKsa [7]2 years ago

3 0

Answer:

The distribution of electrons in energy levels is responsible for the shape of the periodic table.

Explanation:

Henry Moseley in the 1900s re-stated the periodic law by changing the basis of the table to reflect more on the atomic number. The present law is therefore "the properties of elements are a periodic function of their atomic numbers".

Atomic number is the number of electrons in an atom and it is the same as the number of protons for neutral atoms.

In the table, elements having the same number of electrons in the outermost shell of their atoms are placed over one another in vertical columns. Each of the vertical column is known as a group or family while each of the resulting horizontal rows is known as period or row.

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How many grams are in 562 dg? 56.2 g 56,200 g 5.620 g 5.62 g

lana66690 [7]

Answer:

56.2

Explanation:

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2 years ago

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Cutting a piece of paper in half proves that solids have no definite shape. True or False?

erma4kov [3.2K]

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2 years ago

Given the following equation: 2 K3N ---> 6 K + N2 How many moles of N2 can be produced by letting 12.00 moles of K3N react?

myrzilka [38]

The answer will be 12 nitrogen or N2 will be produced because if you changed the coefficient to 12 on the reactant side and distribute, the nitrogen would be 12 when distributed and what happens on one side has to equal to the other side, which is the product side.

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2 years ago

You have 26.7 mL of 0.061 mol/L aqueous potassium hydroxide (KOH(aq)) in a conical flask. In a burette

Natasha2012 [34]

Answer:

9.47 mL

Explanation:

The reaction that takes place is:

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

First we calculate how many KOH moles reacted, using the given concentration and volume of KOH solution:

0.061 mol/L = 0.061 mmol/mL

0.061 mmol/mL * 26.7 mL = 1.6287 mmol KOH

Then we convert KOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

1.6287 mmol KOH * $\frac{1mmolH_2SO_4}{2mmolKOH}$ = 0.8144 mmol H₂SO₄

Finally we calculate the required volume of the H₂SO₄ solution, using the number of moles and given concentration:

0.8144 mmol ÷ 0.086 mmol/mL = 9.47 mL

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2 years ago