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kirill115 [55]
4 years ago
15

What distance formula

Physics
1 answer:
nekit [7.7K]4 years ago
8 0
Y2-y1/x2-x1 is the formula to slope if that's what your asking
You might be interested in
Calculate the electric field intensity at a point 3 cm away from point charge of 3 x 10^-9 C.
lukranit [14]

Answer:

The electric field intensity is <u>30000 N/C.</u>

Explanation:

Given:

Magnitude of the point charge is, q=3\times 10^{-9}\ C

Distance of the given point from the point charge is, d=3\ cm=0.03\ m

Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.

Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:

E=\frac{kq}{d^2}

Plug in k=9\times 10^9\ N\cdot m^2/C^2, q=3\times 10^{-9}\ C, d=0.03\ m. Solve for 'E'.

E=\frac{(9\times 10^9\ N\cdot m^2/C^2)(3\times 10^{-9}\ C)}{(0.03\ m)^2}\\\\E=\frac{27}{0.0009}\ N/C\\\\E=30000\ N/C

Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.

3 0
3 years ago
A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W,
serg [7]

Answer:

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

3 0
3 years ago
The tension at which a fishing line snaps is commonly called the line's strength .what minimum strength is needed for a line tha
marusya05 [52]
Equal the tension of the line to the force needed to stop (deselerate) the mass from a speed of 9.2 ft/s to 0 in 4.4 inches.

Start converting all the information to the SI.

mass, m = 19 lb * [1kg/2.2046lb] = 8.618 kg

speed: 9.2 ft/s * .3048m/ft = .2.80 m/s

distance to stop: 4.4 in * [2.54cm/in]*[1m/100cm] = 0.11176 m

constant acceleration => Vf^2 = Vo^2 - 2ad

Vf = 0 => a= V0^2 / 2d = [2.80m/s]^2 / (2*0.11176m) = 35.1 m/s^2

Use the second Law of Newton

Net force = m*a = 8.618 kg * 35.1 m/s^2 = 302.5 N

Answer: 302.5 N

 
3 0
3 years ago
Earth's atmosphere traps energy from the sun which is a direct result of the trapping of energy by Earth's atmosphere?
Alik [6]
Heat increase causing global warming causing high sea levels
3 0
3 years ago
How much work does a 60.0g bullet that is traveling at 200m/s do and what is the kinetic energy?
lawyer [7]

Answer:

1200000J

Explanation:

Kinetic energy = 1/2 x mass x velocity^2

From the question,

mass =60.0g

Veblcity =200m/s

Therefore

Kinetic energy = 1/2 x 60 x 200^2

1/2 x 60 x 200x200

1/2 x 60 x 40000

30 x 40000

1200000J

7 0
4 years ago
Read 2 more answers
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