1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
baherus [9]
2 years ago
8

What is the density of an object with a mass of 60g and a volume of 2cm3?

Physics
1 answer:
zaharov [31]2 years ago
8 0

m= 60g = 60/1000 Kg = 0.06 Kg v = 2cm3 = 2 * (0.01^3) m3 = 2 *10^-6 m3 Density= m/v = 6 * 10^-2 / 2 *10^-6  =  3 *10^4 Kg/m3

You might be interested in
William made one comment to an employee recently assigned to his team complimenting her on her dress. Later she was reprimanded
Ilya [14]

Answer:

C

Explanation:

William should fully in the investigation. If the only plausible evidence of sexual harassment  is a subtle compliment of an employee's choice or way of dressing. Such comments may be opinionated but are insufficient or a weak evidence for a sexual harassment case.    

5 0
2 years ago
Read 2 more answers
A man supports himself and the uniform horizontal beam pulling the rope with a force T.The weights of men and the beam are 883 N
artcher [175]

Answer:

T=502.5N

Ax=171.8N

Explanation:

The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:

vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0

Now  

horizontal forces sum = Ax - Tcos70

Now Moment about B

-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0

Ay=453.6N

Now substitute in sum of vertical forces T=502.5N

Ax=171.8N

3 0
2 years ago
Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example
iragen [17]

Given Information:

Magnetic field = B = 1×10⁻³ T

Frequency = f = 72.5 Hz

Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m

Required Information:

Maximum Emf = ?

Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

Emf = BAωcos(ωt)

Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

Emf = BAω

Area is given by

A = πr²

A = π(d/2)²

A = π(7.60×10⁻⁶/2)²

A = 45.36×10⁻¹² m²

We know that,

ω = 2πf

ω = 2π(72.5)

ω = 455.53 rad/sec

Finally, the emf is,

Emf = BAω

Emf = 1×10⁻³*45.36×10⁻¹²*455.53

Emf = 20.66×10⁻¹² volts

Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts

8 0
2 years ago
Suppose a man pushes a crate with a force of 20 N north. What is the magnitude and direction of the reaction force?
Goryan [66]

20 N north because He is pushing it 20 newtons north.

5 0
2 years ago
Similarity between heat and temperature
pentagon [3]
Heat is a temperature and temperature has many factors such and cold, warm, and hot.
7 0
2 years ago
Other questions:
  • A lightbulb becoming lit is an example of this
    11·2 answers
  • A man is dragging a trunk up the loading ramp of a mover's
    15·1 answer
  • Arun places a beaker of water on a hotplate and turns the hotplate on. The temperature in the room is 25 ºC. After the water hea
    8·1 answer
  • What are the balanced forces for someone in a parachute? A. Gravity and Earth B. Gravity and air resistance C. Gravity and centr
    9·2 answers
  • A small object with mass 1.30 kg is mounted on one end of arod
    10·1 answer
  • An 8 Ω resistor is connected to a battery. The current that flows in the circuit is 2 A. Calculate the voltage of the battery.
    6·1 answer
  • Please help, thank you to anyone who answers! Will mark brainliest, give a thanks and a 5 star.
    12·1 answer
  • An element's atomic number is 13. How many protons would an atom of this element have?
    5·1 answer
  • According to the law of conservation of matter, which statement about chemical reactions is true?
    14·1 answer
  • Which ammeter will have the biggest reading
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!