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3 years ago

suppose the spring in the sample problem is replaced with a spring that stretches 36 cm from its equilibrium position

1 answer:

amm18123 years ago

3 0

The gravitational force is acting downward as the spring is held vertically. Therefore, spring is stretched downward and the force is directly proportional to the stretched distance. The product of the mass and the gravitational acceleration gives gravitational force.

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A 3.00-kg rifle fires a 0.00500-kg bullet at a speed of 300 m/s. Which force is greater in magnitude:(i) the force that the rifl

alekssr [168]

Answer:

C. both forces have the same magnitude

Explanation:

Here the action force is equal to the reaction force in accordance with the Newton's third law of motion.

Also when we apply the conservation of momentum so that the momentum bullet and the momentum of the gun are equal and according to the second law of motion by Newton, we have force equal to the rate of change in momentum.

We have the equation for momentum as:

$p=m.v$

Newton's second law is Mathematically given as:

$F=\frac{dp}{dt}$

Momentum is constant and the reaction time is equal, so the force exerted will also be equal.

7 0

2 years ago

A 65.8-kg person throws a 0.0413 kg snowball forward with a ground speed of 32.5 m/s. A second person, with a mass of 58.7 kg, c

guapka [62]

Answer:

$v_{1} = 2.490\,\frac{m}{s}$

$v_{2} = 0.023\,\frac{m}{s}$

Explanation:

The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:

First Person

$(65.8\,kg)\cdot (2.51\,\frac{m}{s}) = (65.8\,kg)\cdot v_{1} + (0.0413\,kg)\cdot (32.5\,\frac{m}{s} )$

Second Person

$(0.0413\,kg)\cdot (32.5\,\frac{m}{s})+(58.7\,kg)\cdot (0\,\frac{m}{s})=(0.0413\,kg+58.7\,kg)\cdot v_{2}$

The final velocities of the two people after the snowball is exchanged is:

$v_{1} = 2.490\,\frac{m}{s}$

$v_{2} = 0.023\,\frac{m}{s}$

6 0

3 years ago

an object is producing a sound that has a wavelength in air of 2.69m. If the speed of sound in air is 346m/s, what is the freque

Misha Larkins [42]

Answer:

129.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 346 m / sec

wavelength ( λ ) = 2.69 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 346 / 2.69 Hz

= > f = 34600 / 269 Hz

= > f = 129.74 Hz

Hence, frequency of sound is 129.74 Hz.

5 0

2 years ago

You are given an unknown liquid and asked to determine its identity. You can measure only one physical property. You decide to h

11Alexandr11 [23.1K]

B boiling point because you used heat and it turned to vapor so it was boiled

4 0

3 years ago

Which statements accurately describes the waste generated by nuclear reactions ? check all that apply.

Neko [114]

A) its 's hazardous for hundreds to thousand of year B) Some waste can be recycled and used again is the answer

4 0

3 years ago