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Zanzabum
4 years ago
8

What is 3 % of 800 ?

Mathematics
2 answers:
AnnyKZ [126]4 years ago
7 0
Hey! To do this you have to do 0.03 x 800 to get 24. Good luck!



<span>Hope that this helped! If it did, please give me a good rating and mark me brainliest for my hard work. Thanks!</span>
SIZIF [17.4K]4 years ago
5 0
3% of 800 is 24. I got that by figuring out that 3/800, rounded up is 24
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Which one is correct? Please hurry...the audio is just reading the question.
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Answer:

n = 18

Step-by-step explanation:

18/27 = 12/n

18 * n = 12 * 27

18n = 324

n = 324/18

n = 18

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3 years ago
HELP ME PLEASE!!!!!!!!
ale4655 [162]
I think this is how you do it

4 0
3 years ago
The graph shows the yearly balance, in dollars, in an investment account.
Temka [501]

Take 2 points

  • (0,5000)
  • (2,4000)

Slope:-

\\ \rm\Rrightarrow m=\dfrac{4000-5000}{2}=-500

Equation in point slope form

\\ \rm\Rrightarrow y-5000=-500(x)

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6 0
2 years ago
How do you solve -10+2y=7
Eva8 [605]

Answer

y = \frac{17}{2}

Step-by-step explanation:

-10 + 2y = 7

Add 10 to both sides of the equation

2y = 7 + 10

Add 7 and 10

2y = 17

divide each term in 2y=17 by 2

\frac{2y }{2} = \frac{17}{2}

Divide y by 7

y = \frac{17}{2}

<u>Hope this helps </u>

5 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
3 years ago
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