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Zanzabum
3 years ago
8

What is 3 % of 800 ?

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0
Hey! To do this you have to do 0.03 x 800 to get 24. Good luck!



<span>Hope that this helped! If it did, please give me a good rating and mark me brainliest for my hard work. Thanks!</span>
SIZIF [17.4K]3 years ago
5 0
3% of 800 is 24. I got that by figuring out that 3/800, rounded up is 24
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Find the missing length on the triangle. Round your answer to the nearest tenth if
Ierofanga [76]

Answer:

D. 10.6

Step-by-step explanation:

Using Pythagoras' theorem

hyp² = side ² + side²

hyp² = 7² + 8²

hyp² = 49 + 64

hyp² = 113

hyp = sqrt of 113

hyp = 10.6

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>MY ANSWER</em><em> </em><em>IS HELPFUL</em><em> </em><em>;</em><em>)</em><em> </em>

4 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean
Nastasia [14]

Answer:

a) \bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

b) ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n=80 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

For this case we can calculate the mean like this:

\bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

Part b

For this case is the sample size is doubled the margin of error would be:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

5 0
2 years ago
Charles is 20% heavier than Edith. If Charles weighs 60kg, what is Edith's weight?​
ddd [48]

Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

4 0
1 year ago
Por que razón los números fraccionarios y decimales no tienen un sucesor y un antecesor​
stepan [7]

Answer:

ummmm what did he sayyyyyyyyy

Step-by-step explanation:

3 0
2 years ago
Find the coordinates of the midpoint of the segment whose endpoints are R(9, 3) and S(-1, -9).
amm1812

Answer:

(4, -3 )

General Formulas and Concepts:

<u>Pre-Algebra I</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Midpoint Formula: (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )

Step-by-step explanation:

<u>Step 1: Define</u>

R (9, 3)

S (-1, -9)

<u>Step 2: Find midpoint</u>

  1. Substitute:                    (\frac{9-1}{2}, \frac{3-9}{2} )
  2. Subtract:                       (\frac{8}{2}, \frac{-6}{2} )
  3. Divide:                          (4, -3 )
4 0
2 years ago
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