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Damm [24]
3 years ago
6

This is cylinder .. Tell the following questions

Mathematics
2 answers:
Blababa [14]3 years ago
4 0
Faces-3. Edges-2. Vertices-0
Shalnov [3]3 years ago
3 0

Answer:

Number of faces:Two

Number of edges:NONE

Number of vertices:NONE

Which faces have same shape and size:The bottom and top circle

<em>I hope I helped!</em>

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Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

3 0
3 years ago
Given that (x+2) is a factor of x^3+8, find the other quadratic factor.
Semmy [17]
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
3 0
2 years ago
Multiply Conjugates <br><br><br><br><br> (r+1/4)r-1/4)
Mamont248 [21]

Answer:

\large\boxed{\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\dfrac{1}{16}}

Step-by-step explanation:

\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\left(\dfrac{1}{4}\right)^2=r^2-\dfrac{1^2}{4^2}=r^2-\dfrac{1}{16}

8 0
3 years ago
Read 2 more answers
Evaluate 12x2 + 39x + 30 at x = 3.
ycow [4]

Answer:

255

Step-by-step explanation:

12x^(2) + 39x + 30

x = 3

Substitute in"3" for "x" and solve;

12(3)^(2) + 39(3) + 30

= 12 * 9 + 117 + 30

= 108 + 117 + 30

= 255

3 0
3 years ago
Read 2 more answers
Question 2 What percent is shaded green? Type your answer on the line. *
bekas [8.4K]

Answer:

14 % you just gotta count the green boxes and make it a percentage

6 0
3 years ago
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