Answer:
t1= 1.1475 sec
t2=9.48 sec
Step-by-step explanation:
This question asking for the time when an object reach a specific height. I will explain what the formula stand for to make this easier.
h= height = 174feet
v0= initial velocity = 170 feet/s
t= time
h0= initial height= ground level = 0
The question have predetermined formula for the height, so we should use it instead of formula that involve gravity value.
h= -16 +v0t + h0t
174 feet = -16 + 170 feet/s x t + 0 x t
-16 + 170 feet/s x t - 174 feet = 0
8 - 85 feet/s x t + 87 feet = 0
This equation will be hard to solve since its value in fraction, so lets use the quadratic formula
t1=
t1= 1.1475
t2=
t2=9.48
the second one is the answer <i think>
X + (x + 8) = 66
2x = 58
x = 29
29 + 8 = 37
29 + 37 = 66
Answer:
B. (8, -54)
Step-by-step explanation:
y = -7x + 2
Check to see if the point makes the equation true
A. (1,2) 2 = -7(1)+2 = -7+2 = 5 False
B. (8, -54) -54 = -7(8)+2 = -56+2 = -54 True
C. (5, -35) -35 = -7(5) +2 = -35+2 = -33 False
D. (1, -7) -7 =-7(1)+2 = --7+2 = -5 False