Answer:
35Cl = 75.9 %
37Cl = 24.1 %
Explanation:
Step 1: Data given
The relative atomic mass of Chlorine = 35.45 amu
Mass of the isotopes:
35Cl = 34.96885269 amu
37Cl = 36.96590258 amu
Step 2: Calculate percentage abundance
35.45 = x*34.96885269 + y*36.96590258
x+y = 1 x = 1-y
35.45 = (1-y)*34.96885269 + y*36.96590258
35.45 = 34.96885269 - 34.96885269y +36.96590258y
0.48114731 = 1,99704989y
y = 0.241 = 24.1 %
35Cl = 34.96885269 amu = 75.9 %
37Cl = 36.96590258 amu = 24.1 %
I think it looks good but some grammars are wrong i suggest trying to put it on grammarly and just check it out its just my suggestion and not doing this for points so you can delete this if it doesnt help
May i please have a(n) answer choices please because it would be a lot better if it was like that and then ill answer it
Https://us-static.z-dn.net/files/d49/33d4ec86853ef95e6f6c14242c663be4.png
Your question isn’t typed right :(