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Dahasolnce [82]
3 years ago
5

The word root for a group of microorganisms living together is a. steriliz. b. prodrom. c. coloniza. d. nosocomi.

Chemistry
1 answer:
UkoKoshka [18]3 years ago
7 0

The answer is C) Coloniza.

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In which of the following cases does the reaction go to farthest to completion ?
Mashcka [7]

Answer:

k=10^{3}

Explanation:

k stand for equilibrium constants in terms of reaction

The higher the value of an equilibrium constant the faster the equilibrium reaction comes to completion.

Consider the example below:

R_{1}\ + R_{2}⇄P_{1}\ + P_{2}

where

The\ equilibrium\ constant\ K = \frac{P_{1}P_{2}}{R_{1}R_{2}}

For a faster reaction the numerator i.e. the right hand side of the equation have to be higher than the left hand side (the denominator). therefore the higher the numerator, the higher the value of the equilibrium constant and the faster the reaction get to completion thus option c is correct.

5 0
3 years ago
How many moles are in 8.11 X 1020 molecules of CH4?<br> &lt; &gt;
Gre4nikov [31]

Answer:

6.022⋅1023

Explanation:

4 0
3 years ago
What is the Bohr model for potassium?
Zolol [24]
This is Bohrs model for potassium

4 0
3 years ago
Read 2 more answers
In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga
Reptile [31]

Answer:

The rate at which ammonia is being produced is 0.41 kg/sec.

Explanation:

N_2+3H_2\rightarrow 2NH_3 Haber reaction

Volume of dinitrogen consumed in a second = 505 L

Temperature at which reaction is carried out,T= 172°C = 445.15 K

Pressure at which reaction is carried out, P = 0.88 atm

Let the moles of dinitrogen be n.

Using an Ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.88 atm\times 505 L}{0.0821 atm l/mol K\times 445.15 K}=12.1597 mol

According to reaction , 1 mol of ditnitrogen gas produces 2 moles of ammonia.

Then 12.1597 mol of dinitrogen will produce :

\frac{2}{1}\times 12.1597 mol=24.3194 mol of ammonia

Mass of 24.3194 moles of ammonia =24.3194 mol × 17 g/mol

=413.43 g=0.41343 kg ≈ 0.41 kg

505 L of dinitrogen are consumed in 1 second to produce 0.41 kg of ammonia in 1 second. So the rate at which ammonia is being produced is 0.41 kg/sec.

6 0
3 years ago
How many moles of water are in a beaker with 50 mL?
tatiyna

Answer:

Number of moles = 2.8 mol

Explanation:

Given data:

Number of moles of water = ?

Volume of water = 50 mL

Density of water = 1.00 g/cm³

Solution:

1 cm³ =  1 mL

Density = mass/ volume

1.00 g/mL = mass/ 50 mL

Mass = 1.00 g/mL× 50 mL

Mass = 50 g

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 50 g / 18 g/mol

Number of moles = 2.8 mol

5 0
3 years ago
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