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Kazeer [188]
3 years ago
9

Why does Earthquakes occur?

Chemistry
1 answer:
Annette [7]3 years ago
6 0
Shifting plates, underwater volcanoes. many different variables come in play
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Which of the following is the largest volume? 4.0 x 101 m3 3.8 x 107 cm3 3.8 x 105 dm3 3.8 x 108 mm3
fiasKO [112]
Answer : Option A) 4.0 X 101 m^{3} 

Explanation : As per the measurement chart the greatest metric system is measured in meters.

So the rest values are given in the form of metric values which are obviously less than that of meters. values of centimeters, decimeter and millimeters are less than that of meters.
8 0
3 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
Five solutions on how to prevent air pollution ​
I am Lyosha [343]

Answer:

Reduce number of trips

Avoid burning leaves

Avoid using garden equipments

Reduce the use of wood stove

Avoid gas-powered lawn.

Explanation:

7 0
3 years ago
How many electrons are in their outer shell?
quester [9]
Is there an attachment because it depends on the element.
5 0
3 years ago
Determine the mass of 2.4 x 10^24 atoms of gold?​
Scorpion4ik [409]

Answer:

Mass = 785.9 g

Explanation:

Given data:

Atoms of gold = 2.4 × 10²⁴ atoms

Mass of gold = ?

Solution:

First of all we will convert the number of atoms into moles.

2.4 × 10²⁴ atoms × 1 mol/ 6.02 × 10²³ atoms

number of moles = 3.99 mol

Now we will determine the mass of gold.

Mass = number of moles × molar mass

Mass =  3.99 mol × 196.97 g/mol

Mass = 785.9 g

8 0
3 years ago
Read 2 more answers
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