How is an image formed by a plane mirror
1 answer:
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Answer:
Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from
The answer to the question is
The speed of the electron when it is 10.0 cm from charge Q₁
= 7.53×10⁶ m/s
Explanation:
To solve the question we have
Q₁ = 3.45 nC = 3.45 × 10⁻⁹C
Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C
2·d = 50.0 cm
a = 10.0 cm
q = -1.6×10⁻¹⁹C
Also initial kinetic energy = 0 and
Initial electric potential energy =
Final kinetic energy due to motion = 0.5·m·v²
Final electric potential energy =
From the energy conservation principle we have
Solving for v gives
where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg
gives v =7528188.32769 m/s or 7.53×10⁶ m/s
= 7.53×10⁶ m/s
The period of the pendulum is directly proportional to the square root of the length of the pendulum
Explanation:
The period of a simple pendulum is given by the equation
where
T is the period
L is the length of the pendulum
g is the acceleration of gravity
From the equation, we see that when the length of the pendulum increases, the period of the pendulum increases as the square root of L, . This means that
The period of the pendulum is directly proportional to the square root of the length of the pendulum
From the equation, we also notice that the period of a pendulum does not depend on its mass.
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