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anastassius [24]
3 years ago
5

A bumblebee buzzes past you at 3 m/s. The frequency of the hum made by its wings is 152 Hz. Assume the speed of sound to be 342

m/s. What is the observed frequency of the hum as the bumblebee approaches you?
155 Hz
153 Hz
150 Hz
149 Hz
Physics
2 answers:
lys-0071 [83]3 years ago
6 0

Answer: 153 Hz

Explanation:

The apparent frequency heard by the listener is given by Doppler effect which states that apparent frequency heard by listener varies if the there is relative motion between the source and the listener.

In the given situation, observer is stationary and source of sound is approaching the listener. Thus,

f_o=f_s(\frac{v}{v-v_s})

f_s=152 Hz\\ v = 342 m/s \\ v_s = 3 m/s

\Rightarrow f_o = 152 Hz (\frac{342m/s}{(342-3)m/s} )= 153 Hz

Vadim26 [7]3 years ago
5 0
It is 153 Htz I hope that helps :)
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Where,

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2 years ago
The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl
Nuetrik [128]
<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

<h3>1)</h3>

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

                        = 0

<h3>2)</h3>

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

                            = 2(cos(24)(3.6))

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<em />

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Answer:

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Explanation:

Given,

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We know,

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Hence, the magnetic field is equal to B =  0.129 T

3 0
3 years ago
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