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3 years ago

At which position is the southern hemisphere experiencing spring?

Physics

2 answers:

Sauron [17]3 years ago

8 0

Answer:

Option (4)

Explanation:

When the earth's tilt is oriented towards the sun, then this condition depicts that it is summer in the northern hemisphere, whereas in the southern hemisphere it is winter. So the seasons that occur at different times in both the hemisphere are opposite to one another.

In the southern hemisphere, the spring season starts approximately from the starting of September and ends in the month of November.

So from the given image, it can be concluded that point D is the position in which the Southern hemisphere experiences the spring season.

Thus, the correct answer is option (4).

HACTEHA [7]3 years ago

3 0

The answer is point B.

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Ther are several differences between chemical and physical changes. Which process is an example of a chemical change?

slamgirl [31]

Answer:

A physical change is the change of the shape or color.

Explanation:

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3 years ago

Read 2 more answers

1) How does the frequency of sound affect the speed of sound?

Travka [436]

Changing frequency of sound does not change the speed of the sound.

Explanation:

Speed of the sound gets altered when the sound travels from one medium to another.
Change in frequency does not affect the speed of the sound and speed is affected by the properties of the medium through which it travels.
Therefore, to change the speed of the sound, the properties of the medium needs to be changed.

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3 years ago

A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on

postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0

3 years ago

A solenoid with 500 turns, 0.10 m long, carrying a current of 4.0 A and with a radius of 10-2 m will have what strength magnetic

lakkis [162]

Answer:

Therefore,

Strength magnetic field at its center, B

$B = 2.51\times 10^{-2}\ T$

Explanation:

Given:

Turn = N = 500

length of solenoid = l = 0.10 m

Current, I = 4.0 A

Radius, r = 0.01 m

To Find:

Strength magnetic field at its center, B = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

$\int\ {B} \, ds = Bl=\mu_{0}NI$

Where,

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

$\mu_{0}=Permeability\ in\ free\ space = 4\pi\times 10^{-7}\ Tm/A$

Therefore,

$B =\dfrac{\mu_{0}NI}{l}$

Substituting the values we get

$B =\dfrac{4\times 3.14\times 10^{-7}\times 500\times 4}{0.10}=2.51\times 10^{-2}\ T$

Therefore,

Strength magnetic field at its center, B

$B = 2.51\times 10^{-2}\ T$

4 0

4 years ago

If a small motor does 520 J of work to move a toy car 260 m in 3.0 seconds, how much power is being applied by the motor?

Lubov Fominskaja [6]

Answer:

P = 173.33 [W]

Explanation:

Power is defined as the amount of work done over a given time.

W = work = 520 [J]

t = time = 3 [s]

P = power [w]

Therefore by working relationship over time we can calculate the power.

$P =W/t\\P = 520/3\\P=173.33[W]$

4 0

3 years ago