The change in frequency noticed by observers on sub b is : 2.66 Hz before the submarines pass each other.
<u>Given data:</u>
New speed of Sub b ( Vb ) = 12.4 m/s
F₁ = 1416.44 Hz
Frequency of sonar wave ( Fₐ ) = 1400 Hz
Speed of sound in water ( V ) = 1533 m/s
Speed of submarine A ( Va ) = 8.4 m/s
<h3>Determine the change in frequency observed on sub B </h3>
The change in frequency can be calculated using the formula below
F₁' = Fₐ ( V + Vb / V - Vₐ )
= 1400 ( 1533 + 12.4 / 1533 - 8.4 )
= 1400 ( 1545.4 / 1524.6 )
= 1419.1 Hz
Final step : <u>determine the change in frequency </u>
ΔF = F₁' - F₁
= 1419.1 - 1416.44
= 2.66 Hz.
Hence we can conclude that The change in frequency noticed by observers on sub b is : 2.66 Hz.
learn more about change in frequency : brainly.com/question/254161
You need to subtract the atomic number from the atomic mass to find the # of neutrons.
Answer:
The order is 2>4>3>1 (TE)
Explanation:
Look up attached file
The correct answer is letter c. Enthalpy (H). Entrophy means the measure of the degree of disorder. Gibbs energy formulated by Josiah Willard Gibbs and it is the energy associated with a chemical reaction to do work.Fusion is the combining light nuclei into a heavier nucleus.
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, and can be calculated by means of the following expression.
where:
P = Momentum [kg*m/s]
m = mass = 10 [g] = 0.01 [kg]
v = velocity = 400 [m/s]
i)
![P=0.01*400\\P=4[kg*m/s]](https://tex.z-dn.net/?f=P%3D0.01%2A400%5C%5CP%3D4%5Bkg%2Am%2Fs%5D)
ii)
The momentum of the gun is equal to zero, because it does not move before being fired, the weapon only moves after having fired the weapon.
iii)
Since the momentum is conserved before and after the shot, the same momentum given to the bullet is equal to the momentum received by the gun.
![v_{recoil}=P/m\\v_{recoil}= 4/2\\v_{recoil}=2[m/s]](https://tex.z-dn.net/?f=v_%7Brecoil%7D%3DP%2Fm%5C%5Cv_%7Brecoil%7D%3D%204%2F2%5C%5Cv_%7Brecoil%7D%3D2%5Bm%2Fs%5D)
