3 years ago

When expressing the unit for work, which of the following is the correct choice?

1 answer:

n200080 [17]3 years ago

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You didn't say the following answers but it's Joule (J). If this answer doesn't match the offered ones, you can ask me again

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proton is accelerated to a speed of 0.93c, what is the 1. A proton has a mass of 1.673 x 10-27 kg. If the proton is accelerated

coldgirl [10]

Answer : The correct option is, (B) $1.3\times 10^{-18}kg.m/s$

Explanation : Given,

Mass of proton = $1.673\times 10^{-27}kg$

Speed of proton = 0.93 c

Formula used for relativistic momentum of the proton is:

$p=\frac{m_ov}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

p = relativistic momentum of the proton

$m_o$ = mass of proton

v = speed of proton

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$p=\frac{(1.673\times 10^{-27}kg)\times (0.93c)}{\sqrt{1-\frac{(0.93c)^2}{c^2}}}$

$p=\frac{(1.55589\times 10^{-27}c)}{0.367}$

$p=\frac{(1.55589\times 10^{-27})\times (3\times 10^8)}{0.367}$

$p=1.272\times 10^{-18}kg.m/s\approx 1.3\times 10^{-18}kg.m/s$

Therefore, the relativistic momentum of the proton is, $1.3\times 10^{-18}kg.m/s$

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You hear three beats per second when two sounds tones are generated. The frequency of one tone is known to be 610 Hz. The freque

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The frequency of the other wave is 613 Hz or 607 Hz.

The difference between the frequencies of two waves is called the beat frequency.

Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.

Which has a higher frequency is not mentioned. Therefore, there are two possibilities.

Δf = | 610 - 613 | = 3

Δf = | 610 - 607 | = 3

Therefore, the frequency of the other wave is 613 Hz or 607 Hz.

Learn more about beat frequency here:

brainly.com/question/14157895

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