Hello!
26xy(x + 5)(y - 4) ÷ 13x(y - 4) =
= 2xy × (x + 5) × (y - 4)x × (y - 4) =
= 2x²y × (x + 5) × (y - 4) × (y - 4) =
= 2x²y × (x + 5) × (y - 4)² =
= 2 × [x × (y - 4)]² × y × (x + 5) =
= 2(xy - 4x)² × y × (x + 5) =
= (2xy + 10y) × (x²y² - 8x²y + 16x²) =
= 2x³y³ - 16x³y² + 32x³y + 10x²y³ - 80x²y² + 160x²y
Good luck! :)
Answer:
x = -6, or x = 7 is the ONLY correct solution of the given equation ![x^{2} + x - 30 = 12.](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20%3D%2012.)
Step-by-step explanation:
Here, the given expression is ![x^{2} + x - 30 = 12.](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20%3D%2012.)
or the standard form of the above expression is ![x^{2} + x - 30 - 12 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2030%20-%20%2012%20%3D%200)
or, ![x^{2} + x - 42 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20x%20-%2042%20%3D%200)
Now, if the equation is of the form![ax^{2} + bx + c = 0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%20%2B%20bx%20%2B%20c%20%3D%200)
Then, b = SUM OF THE ROOTS
and c = PRODUCT OF THE ROOTS
Similarly, in the above expression:
b = 1 = Sum of roots
and c = -42 = Product of the roots.
Here, for x = -6, or x = 7:
Sum of Roots = -6 + 7 = 1
Product of roots = (-6)(7) = -42
Hence, x = -6, or x = 7 is the ONLY correct solution of the given equation.
Answer:
Can't a computEr do thi$?
Step-by-step explanation:
32= Space
36= $
39= '
63=?
65-90 A-Z where A=65 and Z=90,
97-122 a-z where a=97 and z=122;
These are the necessary key to decoding this ASCII message in Base 10.
The Code
67 97 110 39 116 32 97 32 99 111 109 112 117 116 69 114 32 100 111 32 116 104 105 36 63
decoded is written as:
Can't a computEr do thi$?
Translation left 3 units: subtract 3 from the original x coordinate --> 4-3=1
Reflection across y-axis: change the sign of the x coordinate --> 1 => -1
Final answer: (-1, 3)
Answer:
average mass of 4 boys=45
or, average mass of 4 boys=sum of weight of 4 boys/4
or,45=total weight/4
therefore, total weight=180kgs
when a new boy joins average mass becomes 40,so,
average mass of 5 boys=40
or,avaerage mass of 5 boys=sum of weights of all 5 boys/5
or,40=(180+x)/5[since the total weight of 4 boys was 180 kgs from the previous calculation and considering 'x' as the weight of the new boy]
or,200=180+x
so,x=200-180
x=20
therefore the mass of the fifth boy is 20kg