How can one show that elements that have different appearances have similar chemical properties?
1 answer:
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The boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.
has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between
and
ions.
Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.
and
will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.
Hence, the boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
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Answer:
Force of attraction = 35.96 N
Explanation:
Given: charge on anion = -2
Charge on cation = +2
Distance = 1 nm = m
To calculate: Force of attraction.
Solution: The force of attraction is calculated by using equation,
---(1)
where, q represents the charge and the subscripts 1 and 2 represents cation and anion.
k =
F = force of attraction
r = distance between ions.
Substituting all the values in the equation (1) the equation becomes
Force of attraction = 35.96 N