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likoan [24]
4 years ago
5

What is the name for SO2

Chemistry
1 answer:
Tanzania [10]4 years ago
7 0
Sulphur Dioxide. Toxic. Don't eat it.
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Adenosine triphosphate (ATP) is the main energy currency used in cells. ATP hydrolysis is coupled with unfavorable reactions, ma
kotegsom [21]

Answer:

<em>Thioesters- the Sulfur-Carbon bond is hydrolyzed, e.g. AcetylCoA</em>

<em>Reduced cofactor- These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized, e.g. Ubiquinol</em>

<em>Phosphorylated compounds- These compounds yield H₂P0₄⁻ upon hydrolysis, e.g. Phosphocreatine</em>

Explanation:

<em>Thioesters</em><em> are esters in which the linking oxygen atom is replaced by a sulphur atom. </em>They are the product of esterification between a carboxylic acid and a sulfhydryl group (thiol). They have the functional group R–S–CO–R'. Thioesters are common intermediates in many biosynthetic reactions. Examples include malonyl-CoA, acetyl-CoA, and propionyl-CoA. <em>In the hydrolysis of thioesters, the sulfur-carbon bond is hydrolyzed.</em>

<em>Cofactors</em><em> can be either organic or inorganic molecules that are required by enzymes to function. Cofactors can be oxidized or reduced for the enzymes to catalyze the reactions.</em>  Examples include, NAD, FAD, NADP, <em>Coenzyme Q₁₀.</em> Coenzyme Q₁₀ exists in three redox states, fully oxidized, partially reduced, and fully reduced. Ubiquinol is the reduced (electron-rich) form of coenzyme Q₁₀. Coenzyme Q₁₀ is vital for proper transfer of electrons within the mitochondrial oxidative respiratory chain, whose main function is to produce adenosine triphosphate (ATP). <em>These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized. </em>

Phosphorylated compounds are compounds with a phosphoryl group (PO₃²⁻) attached to its molecules. <em>These compounds yield an inorganic phosphate (H₂P0₄⁻) upon hydrolysis</em>. Phosphorylation is especially important for protein function as this modification activates or deactivates almost half of the enzymes, thereby regulating their function. Examples include, glucose-1-phosphate, phosphoserine, phosphocreatine, etc.

4 0
3 years ago
Which statement is NOT true about Texas during the 1920s?<br><br><br> Its C
Hatshy [7]
The answer is c because you said it was c lol
5 0
3 years ago
What is the Pauli Exclusion Principle?
Fiesta28 [93]

Answer:

the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins

Explanation:

3 0
3 years ago
THIS IS A THREE PART QUESTION IF YOU CAN HELP IT WOULD BE REALLY APPRECIATED SO I DONT FAIL.
Nostrana [21]

Answer:

1. B = 1.13M

2. A. 8.46%

3. D = 0.0199

Explanation:

1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

Molarity of solution = 2.988 mols/ 2.65 L = 1.13 M

2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

Mass of 2.65 L of water = density × volume

Density of water = 1 Kg/L = 1000 g/L; volume of waterb= 2.65 L

Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

Moles of water = mass /molar mass

Mass of water = 2650 g; molar mass of water = 18 g/mol

Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

6 0
3 years ago
Material of density of 762 kg/m3 occupies a container
konstantin123 [22]

Answer:

The answer is

<h2>0.075 kg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 762 kg/m³

We must first convert the volume from cm³ to m³

1 \:  {cm}^{3}  = 1 \times  {10}^{ - 6}  {m}^{3}

So 99 cm³ will be

9.9 \times  {10 }^{ - 5}  \:  \:  {m}^{3}

So the mass of the material is

mass = 762 \times 9.9 \times  {10}^{ - 5}  \\  = 0.075438

We have the final answer as

<h3>0.075 kg</h3>

Hope this helps you

4 0
4 years ago
Read 2 more answers
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