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xz_007 [3.2K]
3 years ago
15

What is the density of CO2 at a pressure of 0.0079 atm and 227 K? (These are the approximate atmospheric in Mars)

Chemistry
1 answer:
Strike441 [17]3 years ago
6 0

Answer:

The density is 0.0187 g/L

Explanation:

First thing to do here is to calculate the Volume of 1 mole of CO2 using the ideal gas equation

Mathematically;

PV = nRT

thus V = nRT/P

what we have are;

n = 1 mole

R is the molar has constant = 0.082 L•atm•mol^-1•K^-1

P is the pressure = 0.0079 atm

T is temperature = 227 K

Substituting these values, we have;

V = nRT/P = (1 * 0.082 * 227)/0.0079

V = 2,356.20 dm^3

This means according to the parameters given in the question, the volume of 1 mole of carbon iv oxide is 2,356.20 dm^3

But this is not what we want to calculate

What we want to calculate is the density

Mathematically, we can calculate the density using the formula below;

density = molar mass/molar volume

Kindly recall that the molar mass of carbon iv oxide is 44 g/mol

Thus the density = 44/2356.20 = 0.018674136321195 which is approximately 0.0187 g/L

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<u>Answer :</u>

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If you fill your car tire to a pressure of 32 psi (pounds per square inch) on a hot summer day when the temperature is 35°C (95°
Murrr4er [49]
By Gay Lussacs law you can find the pressure. First both temperatures of Celsius must change to Kelvin by adding 273. Temperature one will be 308K and temperature 2 will be 258K
With this info, you can now find the pressure with Lussacs law

P1 = P2
— —
T1 T2

Pressure 1 is given which is 32 psi so just plug it all in and find P2

32 = x
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308 258

308x = 8256 (Cross multiply)

X = 26.8 (divide both sides by 308)

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This makes sense because as temperature increases pressure increases, as well as when temperature decreases, pressure decreases. Since it’s a colder day the pressure will be lower.
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3 years ago
The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
LiRa [457]

Explanation:

(a)  As the given chemical reaction equation is as follows.

           OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.

Hence, equation for rate law of reaction will be as follows.

              Rate = K \times [OCl^{-}] \times [l^{-}]

(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

             1.36 \times 10^{-4} = K \times (1.5 \times 10^{-3})^2

            1.36 \times 10^{-4} = K \times (2.25 \times 10^{-6})

                   K = \frac{1.36 \times 10^{-4}}{2.25 \times 10^{-6}}

                      = 60.4 M^{-1}sec^{-1}

Hence, the value of rate constant for the given reaction is 60.4 M^{-1}sec^{-1} .

(c) Now, we will calculate the rate as follows.

                Rate = K [OCl^{-}][l^{-}]

                         = 60.4 \times (1.8 \times 10^{3}) \times (6.0 \times 10^{4})

                        = 6.52 \times 10^{5}

Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

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Cuantos miles de sulfato de calcio están en 60 gramos de sustancia
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No hay suficiente informacion.
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