Evaluate for x = 2 and y = -4. 1/2^-2x^-3y^5 16 -1/32 -16 -4
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Answer:
The probability that all three have type B+ blood is 0.001728
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a person in the United States has type B+ blood is 12%.
This means that
Three unrelated people in the United States are selected at random.
This means that
Find the probability that all three have type B+ blood.
This is P(X = 3).
The probability that all three have type B+ blood is 0.001728