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3 years ago

Sodium metal and water react to form sodium hydroxide and hydrogen gas:

Chemistry

1 answer:

asambeis [7]3 years ago

8 0

Answer:

Mass of sodium react = 8.63 g

Explanation:

Given data:

Mass of sodium hydroxide produced = 15 g

Mass of sodium react = ?

Solution:

Chemical equation:

2Na + 2H₂O → H₂ + 2NaOH

Number of moles of sodium hydroxide:

Number of moles = mass/ molar mass

Number of moles = 15 g/ 40 g/mol

Number of moles = 0.375 mol

Now we will compare the moles of Sodium and sodium hydroxide.

NaOH : Na

2 : 2

0.375 : 0.375

Mass of Sodium:

Mass = number of moles × molar mass

Mass = 0.375 mol× 23 g/mol

Mass = 8.63 g

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Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all

Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

$n = 4$ .
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Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the $4s$ orbital (fourth $s$ orbital.)

The quantum number $n$ (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, $n = 4$ for this electron.

The quantum number $l$ (the angular momentum quantum number) specifies the shape ( $s$ , $p$ , $d$ , etc.) of an electron. $l = 1$ for $s\!$ orbitals (such as the one that contains this electron.

Quantum numbers $n$ and $l$ specify the shape of an orbital. On the other hand, the magnetic quantum number $m_l$ specifies the orientation of these orbitals in space.

However, $s$ orbitals are spherical. Regardless of the value of $n$ , the only possible $m_l$ value for electrons in $s\!$ orbitals is $m_l = 0$ .

The spin quantum number $m_s$ distinguishes between the two electrons in an orbital. The two possible values of $m_s \!$ are $(+1/2)$ and $(-1/2)$ . Typically, the first electron in an orbital is assigned an upward ( $\uparrow$ ) spin, which corresponds to $m_s = (+1/2)$ .