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3 years ago

Oxidation number of Al(OH)4

Chemistry

1 answer:

Kobotan [32]3 years ago

8 0

Explanation:

The sum of all oxidation numbers in a neutral compound is zero. The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion. The oxidation number of oxygen in a compound is usually –2. The oxidation state of hydrogen in a compound is usually +1.

The oxidation state of Al in Al(OH)

−

x+4(+1−2)=−1

∴x=+3

The oxidation state of Mn in MnO

y+2(−2)=0

∴y=+4

thank u

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Answer:

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Explanation:

Given data:

Volume of solution = 250 mL (250 mL × 1 L/1000 mL = 0.25 L)

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3 years ago

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Answer:

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Explanation:

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1 year ago

A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol

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Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

1 gallon = 3.78541 L

4. 50 gallon = 3.785 L x 4.50

So,

initial volume V1 = 17.03 L

final Volume V2 = ?

initial Temperature T1 = 80° F

convert Temperature to Kelvin

T1 = ( 80° F -32) / 1.8 +273

T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

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As we have to find out volume, so rearrange the above equation

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