The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
Answer is: D. Cl (chlorine).
The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).
Barium, potassium and arsenic are metals (easily lost valence electrons), chlorine is nonmetal (easily gain electrons).
Alkaline metals (in this example, potassium) have lowest ionizations energy and easy remove valence electrons (one electron), earth alkaline metals (in this example, barium) have higher ionization energy than alkaline metals, because they have two valence electrons.
Nonmetals (in this example chlorine) are far right in the main group and they have highest ionization energy, because they have many valence electrons.
Answer:
2
Explanation:
In balancing nuclear reactions the mass number and atomic numbers are usually conserved. This implies that from the given equation, the sum of the number of the subscript on the right hand side must be equal to that on the left hand side. This also applies to the superscript:
For the mass numbers(superscript):
235 + 1 = 1 + 139 + 95
236 = 235
This is not balanced
For the atomic number:
92 + 0 = 0 + 53 + 39
92 = 92
This is balanced.
We simply inspect to see how to balance the mass number.
By putting a coefficient of 2 behind the neutron atom, the equation becomes balanced.
Answer and explanation:
The relative rates of free radical halogenation is in the order of,
F₂ (10⁸) > Cl₂ (1) > Br₂ (10⁻¹¹) > I₂ (10⁻²²)
The above order also show a decreasing reactivity from left to right
Hence, reaction of fluorine with alkanes is highly reactive and it is too difficult to control.
The reaction with Cl₂ is moderately fast, while with Br₂ is slow and with I₂ is too slow reaches to equilibrium.
Hence in general we don't prefer radical fluorination of alkanes.
