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natali 33 [55]
4 years ago
13

An object is dropped from a height of 25 meters. At what velocity will it hit the ground?

Physics
1 answer:
Vikki [24]4 years ago
5 0
Data:
h=25 m
v₀=0 m/s
g=9,8 m/s²

we use this formula
h=h₀+v₀.t+(1/2).g.t²
25 m=0 m+0 m/s.t+(1/2).(9,8 m/s²).t²
25 m=4,9 m/s².t²
t²=25 m /4,9 m/s²
t²=5,1 s²
t=√(5,1 s²)=2,26 s 

Now, we calculate the última velocity 
v=v₀+gt
v=0 m/s+9,8 m/s².(2,26 s)=22,14 m/s≈22 m/s

solution: c.)  22 m/s


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For an answer to be completed the units need to be specified why?
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A solenoid inductor has an emf of 0.80 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.20 A pr
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Answer:

The number of turns of the inductor is 2000 turns.

Explanation:

Given;

emf of the inductor, E = 0.8 V

the rate of change of current with time, dI/dt = 10 A/s

steady current in the solenoid, I = 0.2 A

flux per turn, Ф = 8.0 μWb per

Determine the inductance of the solenoid, L

E = L(dI/dt)

L = E / (dI/dt)

L = 0.8 / (10)

L = 0.08 H

The inductance of the solenoid is given by;

L = \frac{\mu_o N^2 A}{l}

Also, the magnetic field of the solenoid is given by;

B = \frac{\mu_o NI}{l}

I is 0.2 A

B = \frac{\mu_oN(0.2)}{l} = \frac{0.2\mu_o N}{l}

\frac{B}{0.2 } = \frac{\mu_o N}{l}

L = \frac{\mu_o N^2 A}{l} \\\\L = \frac{\mu_o N }{l} (NA)\\\\L = \frac{B}{0.2} (NA)\\\\L = \frac{BA}{0.2} (N)

But Ф = BA

L = \frac{\phi N}{0.2} \\\\\phi N = 0.2 L\\\\N = \frac{0.2 L}{\phi} \\\\N = \frac{0.2 *0.08}{8*10^{-6}}\\\\N = 2000 \ turns

Therefore, the number of turns of the inductor is 2000 turns.

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Explanation:

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Destruction Difficult Easy

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