Answer:
The merry-go-round's angular velocity 23.84 RPM
Explanation:
Given;
diameter of merry go round, d = 3 m
radius of the merry go round, R = 1.5 m
mass of the merry go round, m = 300 kg
angular velocity = 23 rpm
velocity of John, v = 4.4 m/s
mass of John, m = 30 kg
Apply conservation of angular momentum;
where;
I is moment of inertia of disk
Substitute in this value in the above equation;
1 rad/s = 9.5493 rpm
2.496 rad/s = 23.84 RPM
Therefore, the merry-go-round's angular velocity 23.84 RPM