Which type of electromagnetic wave often encodes information for sound?

If a projectile hits a stationary target, and the projectile continues to travel in the same direction, the mass of the projecti

nika2105 [10]

The correct arrangement of the question is;

If a projectile hits a stationary target, and the projectile continues to travel in the same direction,

A) the mass of the projectile is less than the mass of the target.

B) the mass of the projectile is equal to the mass of the target.

C) the mass of the projectile is greater than the mass of the target.

D) nothing can be said about the masses of the projectile and target without further information.

E) this is an unphysical situation and will not actually happen.

Answer:

Option C: The mass of the projectile is greater than the mass of the target.

Explanation:

We want to find what will happen when a projectile continues in motion after it hits a target.

Now, for the projectile to keep moving in that direction after it hits the target, it means it had a force bigger than the force of the target to overpower it and force it to move with it.

Now, from law of inertia, Force = ma.

But in this case acceleration is 0 because the speed of the projectile is constant.

Thus, the force depends on the mass. So for a higher force, the mass of the projectile has to be more than that of the stationary object.

Thus, option C is correct

8 0

2 years ago

This is how manganese appears in the periodic table. The arrow is pointing to the atomic of manganese.

Liula [17]

The way an element is shown in the periodic table is called the element's symbol. In the case of manganese, it is Mn. Other information shown alongside the element's symbol is the atomic mass, which for manganese is 55, and the atomic number of the element, which for manganese is 25.

5 0

2 years ago

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A string is stretched and fixed at both ends, 200 cm apart. If the density of the string is 0.015 g/cm, and its tension is 600 N

Gre4nikov [31]

Answer:

<h2>f₀ = 158.12 Hertz</h2>

Explanation:

The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.

$V = \sqrt{\frac{T}{\mu} }$ where T is the tension in the string and $\mu$ is the density of the string

Given T = 600N and $\mu$ = 0.015 g/cm = 0.0015kg/m

$V = \sqrt{\frac{600}{0.0015} }\\ \\V = \sqrt{400,000}\\ \\V = 632.46m/s$

The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.

L = 2m

Substituting the derived values into the formula f₀ = V/2L

f₀ = 632.46/2(2)

f₀ = 632.46/4

f₀ = 158.12 Hertz

Hence the fundamental frequency of the string is 158.12 Hertz

5 0

3 years ago

If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!

Hoochie [10]

Answer:

I can't see the post :/

Explanation:

5 0

2 years ago

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How much heat energy is produced by 0.5 Wh of electrical energy ?

babymother [125]

1.7 Btu

1 watt = 3.41214 Btu/h

1watt * 1h = 3.41214 Btu/h * h

1 = 3.41214 Btu/ (watt*h)/

0.5 watt * h = 0.5 watt*h * 3.41214 Btu/(watt*h) = 1.706 Btu

6 0

3 years ago

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