Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
1 answer:
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Answer:
The object will travel 675 m during that time.
Explanation:
A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.
In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.
In this case, the position is calculated using the expression:
x = xo + vo*t + ½*a*t²
where:
- x0 is the initial position.
- v0 is the initial velocity.
- a is the acceleration.
- t is the time interval in which the motion is studied.
In this case:
- x0= 0
- v0= 0 because the object is initially stationary
- a= 6
- t= 15 s
Replacing:
x= 0 + 0*15 s + ½*6 *(15s)²
Solving:
x=½*6 *(15s)²
x=½*6 *225 s²
x= 675 m
<u><em> The object will travel 675 m during that time.</em></u>
The cost of excavating a space of 84 ft long, 42 ft wide, and 9 ft deep is $45864
Information about the problem:
- Space long= 84 ft
- Space wide= 42 ft
- Space deep= 9 ft
- Cost by yard3 = $39/yd3
- Total cost= ?
To solve this problem, we have to state the equation using the information of the problem:
Calculating the volume of the total space:
space volume = space long * space wide * space deep
space volume = 84 ft * 42 ft * 9 ft
space volume = 31752 ft3
By converting the volume from ft3 to yd3, we have:
31752 ft3 * (0,037037 yd3 / 1 ft3) = 1176 yd3
Calculating the cost of excavating the volume space:
Total cost = space volume * cost by yard3
Total cost = 1176 yd3 * $39/yd3
Total cost = $45864
<h3>What is volume?</h3>It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.
Learn more about volume at: brainly.com/question/12628341
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