The reliability of a two-component product if the components are in parallel is 0.99.
In this question,
The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.
A system contains two components that are arranged in parallel, they are 0.95 and 0.80.
Therefore the system reliability can be calculated as follows
⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )
⇒ 1 - (0.05 × 0.20)
⇒ 1 - 0.01
⇒ 0.99
Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.
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Answer:
6 and 7
Step-by-step explanation:
To evaluate f(3), substitute x = 3 into f(x) , that is
f(3) = 2(3) = 6
To evaluate g(f(3)), substitute f(3) = 6 into g(x)
g(6) = 6 + 1 = 7
The ratio of areas is the square of the scale factor, so that factor is
√(320/180) = 4/3
