<h2>Solution (1) :</h2>
∠<em>y</em><em> </em>and ∠<em>x</em> are alternate interior angles . Both of these angles will be equal in measure when on two parallel lines with a transversal .
<h2>Solution (2) :</h2>
∠y and ∠x are alternate interior angles . Both of these angles will have an equal angle measure when they lie on two parallel lines with a transversal .
<h2>Solution (3) :</h2>
∠y and ∠x vertically opposite angles . Both of these angles will be equal in measure when on two parallel lines with a transversal .
<h2>Solution (4) :</h2>
∠y and ∠x are adjacent angles as well as a linear pair . These angles will sum up to form 180° .
Answer: the first one .00000000058
Step-by-step explanation:
Recall the formula for finding the area of a rectangle:
Area = Length × Width
Recall the formula for finding the perimeter of a rectangle:
Perimeter = 2 ( Length + Width )
Given in your problem:
Area = 40 sq. units
Perimeter = 26 units
Required to solve for:
Length (L) and width (W)
• First, substitute the given to the formula:
Area = Length x Width
40 = L × W ⇒ equation number 1
Perimeter = 2 ( Length + Width )
26 = 2 ( L + W ) ⇒ equation number 2
• Simplifying equation number 2,
13 = L + W
• Rearranging the equation,
L = 13 - W ⇒ equation 3
Substituting equation 3 from equation 1:
( equation 1 ) 40 = (L)(W)
( equation 3 ) L = 13 - W
40 = (13 - W) (W)
40 = 13W - W²
( regrouping ) W² - 13W + 40 = 0
( factoring ) (W - 8) (W - 5) = 0
W - 8 = 0 ; W - 5 = 0
W = 8 ; W = 5
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.
• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.
(equation 3) L = 13 - W
for W = 8 ⇒ L = 13 - 8
L = 5 units
for W = 5 ⇒ L = 13 - 5
L = 8 units
I think that would be C but idk tell me if im right
Answer with Step-by-step explanation:
We are given that

Let g(x,y)=
We have to find the extreme values of the given function


Using Lagrange multipliers



Possible value x=0 or 
If x=0 then substitute the value in g(x,y)
Then, we get 


If
and substitute in the equation
Then , we get possible value of y=0
When y=0 substitute in g(x,y) then we get

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).




Therefore, the maximum value of f on the circle
is
and minimum value of 