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exis [7]
3 years ago
15

Car B is following Car A and has a greater speed than Car A. the two cars are moving in a straight line and in the same directio

n, and have the same mass. in situation one, Car A is traveling at 10 mph and car B at 20 mph. in situation 2, car A is traveling at 30 mph and car B at 40 mph. assuming a perfectly inelastic collision in which the cars stick together after the collision, what will be true?
Physics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

Collision force will be same in both the cases.

Explanation:

A perfectly inelastic collision is said to take place  when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision,  the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.

In situation 1:

Speed of Car A, v_{A} = 10 mph

Speed of Car B, v_{B} = 20 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Now, in the situation 2:

Speed of car A, v_{A} = 30 mph

Speed of car B, v_{B} = 40 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Therefore, Car A and Car B both have the same relative speed, v = 10 m/s

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Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
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Answer:

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Explanation:

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to find out

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solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

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so time will be for B is

time B = distance / velocity

time B = x / 7     ...................1

and

for A distance for meet = ( 10.2 - x ) km

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now equating equation 1 and 2

time A = time B

x / 7  =   ( 10.2 - x )  / 8.9

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so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

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Margaret is the new director of research at a well-known pharmaceutical company. She has been asked to design a set of research
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D

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I just had this question the answer is D  

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