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3 years ago

Which rocky planet has the strongest magnetosphere?

Physics

1 answer:

Nikolay [14]3 years ago

3 0

Earth it has the strongest magnetosphere

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In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of

antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, $a=84\ au= 1.496\times 10^{11}\ m$

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e $T^2=\dfrac{4\pi^2}{GM}a^3$

where G is gravitational constant

M is mass of sun, $M=1.98\times 10^{30}\ Kg$

So, $T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}$

$T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3$

$T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}$

$T^2=59532469.8\times 10^{14}\ s$

$T=7715.7\times 10^7\ s$

since, $1\ sec=3.17\times 10^{-8}\ years$

So, orbital period is approximately 2446 years.

7 0

4 years ago

The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and

diamong [38]

53....................................

Explanation:

6 0

2 years ago

An exoplanet is in an elliptical orbit around a distant star. At its closest approach, the exoplanet is 0.540 AU from the star a

atroni [7]

Answer:

0.71121 km/s

Explanation:

$v_1$ = Velocity of planet initially = 54 km/s

$r_1$ = Distance from star = 0.54 AU

$v_2$ = Final velocity of planet

$r_2$ = Final distance from star = 41 AU

As the angular momentum of the system is conserved

$mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s$

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

7 0

3 years ago

GRAPH INCLUDED PLEASE HELP

swat32

Answer:

10 days

Explanation:

The half-life of a radioactive sample is the time taken for half of the sample to decay.

In the diagram, the half-life corresponds to the time after which the % of cobalt-57 has halved. We can observe the following:

At t=10 days, the % of Co remaining is approximately 45%

At t=20 days, the % of Co remaining is approximately 22%

This means that the sample of cobalt-57 has halved in 10 days, so the half-life of cobalt-57 is 10 days.

5 0

4 years ago

Which change is the best example of a physical change?

murzikaleks [220]

The answer would be a nail rusting, but really it could be any of these.

3 0

3 years ago