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In-s [12.5K]
3 years ago
5

which scenario involves the most work? a.pulling a box with a force of 127 newtons across the floor for 8 meters b.holding a mas

s with a force of 509 newtons in your arms for 150 seconds c.pushing against a brick wall with a force of 20 newtons for 42 seconds d.lifting a rock by exerting an upward force of 500 newtons for 1 meter
Physics
1 answer:
abruzzese [7]3 years ago
6 0
<span>Work can only be said to be done when an applied force results in displacement of the body in the direction of the applied force.

Work can only be said to be done in options a and d

a.pulling a box with a force of 127 newtons across the floor for 8 meters

work = 127 * 8 = 1016J

</span>
<span>d.lifting a rock by exerting an upward force of 500 newtons for 1 meter

Work = 500 N * 1 m = 500 J

Option D has more work.

D</span>
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Three long parallel wires each carry 2.0-A currents in the same direction. The wires are oriented vertically, and they pass thro
blagie [28]

Answer:

21.2\times 10^{-6} T

Explanation:

i  = magnitude of current in each wire = 2.0 A

a  = length of the side of the square = 4 cm = 0.04 m

r  = length of the diagonal of the square = \sqrt{2} a = \sqrt{2} (0.04) = 0.057 m

B = magnitude of magnetic field by wires at A and C

B = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{a} \right )

B = (10^{-7}) \left ( \frac{2(2)}{0.04} \right )

B = 10\times 10^{-6} T

B' = magnitude of magnetic field by wire at B

B' = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{r} \right )

B' = (10^{-7}) \left ( \frac{2(2)}{0.057} \right )

B' = 7.02\times 10^{-6} T

Net magnitude of the magnetic field at D is given as

B_{net} = \sqrt{B^{2}+B^{2}} + B'

B_{net} = \sqrt{2} B + B'

B_{net} = \sqrt{2} (10\times 10^{-6}) + (7.02\times 10^{-6})

B_{net} = 21.2\times 10^{-6} T

8 0
3 years ago
A 50.0-kg projectile is fired at an angle of 30 degrees above thehorizontal with an initial speed of 1.20 x 102 m/s fromthe top
Advocard [28]

Answer:

a)  Em₀ = 42.96 104 J , b)   W_{fr} = -2.49 105 J , c)  vf = 3.75 m / s

Explanation:

The mechanical energy of a body is the sum of its kinetic energy plus the potential energies it has

        Em = K + U

a) Let's look for the initial mechanical energy

      Em₀ = K + U

      Em₀ = ½ m v2 + mg and

      Em₀ = ½ 50.0 (1.20 102) 2 + 50 9.8 142

      Em₀ = 36 104 + 6.96 104

      Em₀ = 42.96 104 J

b) The work of the friction force is equal to the change in the mechanical energy of the body

    W_{fr} = Em₂ -Em₀

     Em₂ = K + U

     Em₂ = ½ m v₂² + m g y₂

     Em₂ = ½ 50 85 2 + 50 9.8 427

     Em₂ = 180.625 + 2.09 105

     Em₂ = 1,806 105 J

     W_{fr} = Em₂ -Em₀

     W_{fr} = 1,806 105 - 4,296 105

     W_{fr} = -2.49 105 J

The negative sign indicates that the work that force and displacement have opposite directions

c) In this case the work of the friction going up is already calculated in part b and the work of the friction going down would be 1.5 that job

We have that the work of friction is equal to the change of mechanical energy

       W_{fr} = ΔEm

       W_{fr} = Emf - Emo

       -1.5 2.49 10⁵ = ½ m vf² - 42.96 10⁴

       ½ m vf² = -1.5 2.49 10⁵ + 4.296 10⁵

       ½ 50.0 vf² = 0.561

       vf = √ 0.561 25

      vf = 3.75 m / s

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What behavior of waves explains why someone can be looking away from you while talking and you still hear them?
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3 years ago
Lonnie pitches a baseball of mass 0.500 kg. The ball arrives at home plate with a speed of 35.0 m/s and is batted straight back
Andreyy89

Answer:

Explanation:

The impulse equation is

Δp = FΔt, where Δp = final momentum - initial momentum, F is the Force exerted on an object, and Δt is the change in time. In this equation,the entire right side defines the impulse. In other words, FΔt is the impulse; thus the change in momentum an object experiences is due to its change in impulse and is directly proportional to it.

Therefore, once we find the change in momentum, that is the impulse the object experiences. Δp = final momentum - initial momentum, where

p = mv and p is momentum.

p_f=(.500)(50.0) so

p_f=25.0 and

p_i=(.500)(35.0) so

p_i=17.5; therefore,

Δp = 25.0 - 17.5 = 7.5\frac{kg*m}{s} which is the unit for momentum

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3 years ago
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Mice21 [21]
The temperature of a gas in which the atoms are moving slowly is (THE COLD). 




THAT'S IT! :)
4 0
3 years ago
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