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3 years ago

Simplify the following expression [ (3x6) ] + (5x2) ] ÷ 7

Mathematics

2 answers:

KonstantinChe [14]3 years ago

6 0

[ (3x6) ] + (5x2) ] ÷ 7
= (18 + 10)/7
= 28/7
= 4

STALIN [3.7K]3 years ago

3 0

The correct answer to this problem is 4

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Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

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3 years ago

Name an event that has a probability of 2/7

damaskus [11]

Answer:

2/7

Step-by-step explanation:

7 balls in a box 3 are red and 2 are yellow and 1 is white what is the probability of find a yellow ball?

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3 years ago

4⋅f(6)−6⋅g(5) need help asap

Leto [7]

Answer:

Step-by-step explanation:

From the blue graph of f(x) we can see that the function value is -6 when x = 6. Similarly, g(5) = -5.

Then: 4*f(6) - 6*g(5) becomes:

4*(-6) - 6*(-5), or

-24 + 30 = 6

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3 years ago

What is the y-intercept of function f? A. 1 B. -1 C. -2 D. 5

shtirl [24]

Answer:

Step-by-step explanation:

The y intercept is when x =0

We need to use the second equation

-x+1 since -2 < 0 <3

0+1

The y intercept is 1

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coldgirl [10]

4,000,000 is 3,567,194 rounded (-:

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3 years ago