1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RSB [31]
4 years ago
12

During casting and solidification, shrinkage includes: a)-Liquid contraction during cooling prior to solidification. b)-Contract

ion during the phase change from liquid to solid. c)-Thermal contraction during cooling to room temperature. d)-All of the above e)-None of the above
Engineering
1 answer:
AysviL [449]4 years ago
7 0

Answer:

(d) all of the above

Explanation:

The option (a) (b) and (c) all are the process of the casting and solidification shrinkage, all the three process are done one by one in casting and solidification shrinkage.

there are mainly three stages in casting and solidification shrinkage these are

  • liquid shrinkage
  • solid to liquid shrinkage
  • contraction process

so from given conclusion it is clear that the statement of option a b and c are correct so the option d will be the correct option

You might be interested in
C programming fundamentals for everyone​
densk [106]

Answer:I am so sorry but here are no questions, thanks for the points

Explanation:Have a nice day

6 0
3 years ago
Suppose that the weights for newborn kittens are normally distributed with a mean of 125 grams and a standard deviation of 15 gr
kherson [118]

(a) If a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

(b) For a kitten to be at 90th percentile, the minimum weight is 146.45 g.

<h3>Weight distribution of the kitten</h3>

In a normal distribution curve;

  • 2 standard deviation (2d) below the mean (M), (M - 2d) is at 2%
  • 1 standard deviation (d) below the mean (M), (M - d) is at 16 %
  • 1 standard deviation (d) above the mean (M), (M + d) is at 84%
  • 2 standard deviation (2d) above the mean (M), (M + 2d) is at 98%

M - 2d = 125 g - 2(15g) = 95 g

M - d = 125 g - 15 g = 110 g

95 g is at 2% and 110 g is at 16%

(16% - 2%) = 14%

(110 - 95) = 15 g

14% / 15g = 0.93%/g

From 95 g to 99 g:

99 g - 95 g  = 4 g

4g x 0.93%/g = 3.72%

99 g will be at:

(2% + 3.72%) = 5.72%

Thus, if a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

<h3>Weight of the kitten in the 90th percentile</h3>

M + d = 125 + 15 = 140 g      (at 84%)

M + 2d = 125 + 2(15) = 155 g   ( at 98%)

155 g - 140 g = 15 g

14% / 15g = 0.93%/g

84% + x(0.93%/g) = 90%

84 + 0.93x = 90

0.93x = 6

x = 6.45 g

weight of a kitten in 90th percentile = 140 g + 6.45 g  = 146.45 g

Thus, for a kitten to be at 90th percentile, the approximate weight is 146.45 g

Learn more about standard deviation here: brainly.com/question/475676

#SPJ1

7 0
2 years ago
que sabemos de la revolución industrial y como ese proceso impulso el uso de los controles eléctricos en las industrias
Alex Ar [27]

Answer:

░░░░░▐▀█▀▌░░░░▀█▄░░░

░░░░░▐█▄█▌░░░░░░▀█▄░░

░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░

░░░░▄▄▄██▀▀▀▀░░░░░░░

░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

▄░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take

░░░░░░░▀███▀█░▄░░ Over brainly

░░░░░░▐▌▀▄▀▄▀▐▄░░

░░░░░░▐▀░░░░░░▐▌░░

░░░░░░█░░░░░░░░█

Explanation:

8 0
3 years ago
Air enters a compressor operating at steady state at 1 atm with a specific enthalpy of
Savatey [412]

Answer:

option C

option A

Explanation:

Enthalpy gained by air= 1023-290

                                       = 733 kJ/kg

Rate of energy gain= mass flow rate × Enthalpy gained by air

                               = 0.1 × 733

                            = 73.3 kJ/s

rate of heat transfer between compressor and air= 77kW

Heat loss by air to surroundings= 77-73.3

                                                     =3.7kW

Enthalpy lost by steam in turbine= 1407.6-1236.4

                                                     = 171.2 Btu/lb

Rate of energy transfer to turbine= Enthalpy lost by steam× mass flow rate

                                                    = 171.2×5

                                                     = 856 Btu/s

Net rate of energy transfer to turbine=rate of  Energy transfer to turbine- rate of heat transfer to turbine

                          = 856-40

                         = 816 Btu/s

8 0
4 years ago
The Bureau of Labor and Statistics predicted that the field of biomedical engineering would increase by 62 percent over the comi
raketka [301]

Answer:

C. It is a continually growing field, and individuals trained in it should not have a problem finding employment.

Explanation:

5 0
3 years ago
Other questions:
  • Some of the wiring under the hood of a hybrid electric vehicle is encased in bright orange covering. That indicates a
    11·1 answer
  • The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas
    11·1 answer
  • A spherical balloon with a diameter of 9 m is filled with helium at 20°C and 200 kPa. Determine the mole number and the mass of
    12·1 answer
  • A classroom that normally contains 40 people is to be air-conditioned with window air-conditioning units of 5 kW cooling capacit
    6·1 answer
  • The free convection heat transfer coefficient on a thin hot vertical plate suspended in still air can be determined from observa
    9·1 answer
  • A has a mass of 7 kg, object B has a mass of 5 lbm, and object C has a mass of 0.5 slug. (a) Which object has the largest mass?
    11·1 answer
  • How is a Doctor Who is a generalist different a specialist?
    12·1 answer
  • The temperature controller for a clothes dryer consists of a bimetallic switch mounted on an electrical heater attached to a wal
    12·1 answer
  • 5 kg of a wet steam has a volume of 2 m3
    8·1 answer
  • In the engineering design process, what do engineers do immediately before
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!