A 50% antifreeze solution is to be mixed with a 90% antifreeze solution to get 200 liters of a 80% solution. How many liters of

Question

Elodia [21]

3 years ago

6

A 50% antifreeze solution is to be mixed with a 90% antifreeze solution to get 200 liters of a 80% solution. How many liters of

the 50% solution and how many liters of the 90% solution will be used?

Chemistry

1 answer:

sergey [27] · Answer 1 · 2022-04-09T00:02:36+03:00

Answer:

50 ltr 150 ltr

Explanation:

this problem can be solved by the mixture and allegation concept which can be clearly understand from bellow figure in which the concentration of solution 1 is 50% and concentration of solution 2 is 90% before mixing after mixing with help bellow concept the ratio of concentration become 10:30

ratio of solution 1 and solution 2 =10:30

=1:3

total mixture is 200 liters

part of solution 1= $\frac{1}{4}$ ×200

=50 liters

part of solution 2= $\frac{3}{4}$ ×200

=150 liters