1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
3 years ago
6

A 50% antifreeze solution is to be mixed with a 90% antifreeze solution to get 200 liters of a 80% solution. How many liters of

the 50% solution and how many liters of the 90% solution will be used?

Chemistry
1 answer:
sergey [27]3 years ago
6 0

Answer:

50 ltr 150 ltr

Explanation:

this problem can be solved by the mixture and allegation concept which can be clearly understand from bellow figure in which the concentration of solution 1 is 50% and concentration of solution 2 is 90% before mixing after mixing with help bellow concept the ratio of concentration become 10:30

ratio of solution 1 and solution 2 =10:30

                                                     =1:3

total mixture is 200 liters

part of solution 1=\frac{1}{4} ×200

                           =50 liters

part of solution 2=\frac{3}{4} ×200

                           =150 liters

You might be interested in
A certain FM radio wave has a frequency of 1.31 x 108 Hz. Given that radio waves travel at
Westkost [7]

Answer:

2.28 m

Explanation:

Use the relationship  

λ=vf

 

to solve for wavelength λ. Substituting the known quantities yields:

λ=vf

 

λ=2.99 x 108 m/s1.31 x 108 Hz

 

λ=2.28 m

 

4 0
3 years ago
What does appeal mean​
Reika [66]
A act of law to remove
3 0
3 years ago
Read 2 more answers
What is always true of an object with a lit of mass ?
sertanlavr [38]

Such an object makes a larger dent in the fabric of space-time than an object with little mass. (It has a greater gravitational attraction than less massive objects)

A greater force is required to accelerate such an object than a less massive object

3 0
3 years ago
Read 2 more answers
A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
4 years ago
32P can be used to make any nucleotide (A, C, G, or T) radioactive. Which of the following explains why this is true?
xxMikexx [17]
B. The answer is: All nucleotides have a phosphorus atom that can be replaced with 32P.

Nucleotides contain a nitrogenous base, a five-carbon sugar, and, at least, one phosphate group. Exactly that phosphate group in the nucleotide has the phosphorus atom. Therefore, the phosphorus atom in the nucleotide can be replaced with radioactive phosphorus-32 (32P). 
3 0
3 years ago
Other questions:
  • What keeps the weather along the north and south Carolina coats milder
    8·1 answer
  • What volume of solution would be present if 40.0 g Caci, would be used to make a 0.600M
    6·1 answer
  • Which sample of copper has atoms with the lowest average kinetic energy?
    13·1 answer
  • Chemical Equations
    11·1 answer
  • What are the tracings of seismometers called
    12·2 answers
  • What determines the mass number of an element? (2 points)
    6·2 answers
  • What is the molar mass of this hydrate?
    15·1 answer
  • 50 Points
    10·2 answers
  • Calculate the density of a sample of 1.00 mole of nh3 at 793mmhg and -9.00 c
    10·1 answer
  • What are the noble gases
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!