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lukranit [14]
4 years ago
10

The charge per unit length on a glass rod is 0.00500 C/m. If the rod is 1 mm long, how many electrons have been removed from the

glass rod?
Chemistry
1 answer:
ehidna [41]4 years ago
5 0

Answer:

3.125 × 10¹³ Electrons

Explanation:

Data provided in the question:

Charge per unit length on rod = 0.00500 C/m

Length of the rod = 1 mm = 1 × 10⁻³ m

Therefore, the total charge on the rod

= Charge per unit length on rod × Length of the rod

= 0.00500 C/m × ( 1 × 10⁻³ m)

= 5  × 10⁻⁶ C

Thus,

Number of electrons removed

=  total charge on the rod ÷ Charge of an electron

= 5  × 10⁻⁶ ÷ (1.6 × 10⁻¹⁹)

= 3.125 × 10¹³ Electrons

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Answer:

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Explanation:

Step 1: Data given

Mass of the sample = 5.54 grams

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Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

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Moles NaOH = 0.00301 moles NaOH

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For 1 mol NaOH we need 1 mol CH3COOH

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Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

Mass CH3COOH = 0.1808 grams

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Mass % = ( 0.1808 / 5.54 ) *100%

Mass % = 3.26 %

3.26 % of vinegar is acetic acid

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