Molar mass Na = 23g/mol
46g = 456/2 = 2mol
1mol = 6.022*10^23 atoms
2mol = 2*6.022*10623
= 1.204*10^24 atoms
<h2>Answer:</h2>
pOH = 4.6
<h2>Explanations:</h2>
The sum of pH and pOH of a solution is 14as shown:
Given the following parameter
pH = 9.4
Substitute the given parameters into the formula to have:
Hence the pOH of the solution of pH of 9.4 is 4.6
I got 17.2 g of AgCl but I’m not sure if it’s correct...