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balandron [24]
3 years ago
12

If u help me i will be very thankful!!

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer:

C

Step-by-step explanation:

(a^{-2}\cdot 8^7)^2= \\\\a^{-2\cdot 2}\cdot 8^{7\cdot 2}= \\\\a^{-4}\cdot 8^{14}

Therefore, the correct answer is C. Hope this helps!

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What is 6.04 in simplest form
Reptile [31]
6 1/25 is the answer
6 0
3 years ago
What is the side length of a square with the area of 20cm2
rodikova [14]

Answer:

S = a² => 20 = a² => a = √20 ≈ 4.5 cm

Step-by-step explanation:

5 0
4 years ago
Solving the equation and something to do with log
Anastaziya [24]

Answer:

m= 1/2.

Step-by-step explanation:

To solve this, we must make the bases equivalent. We can do this by finding the common base which is 5.

We know that 125= 5³ and 25=5², which will help us in this equation. We can rewrite the equation substituting this for the original numbers:

5^{3(2m)} = 5^{2(m+1)} Distribute the exponents to get:

5^{6m} = 5^{2m+2}

Now, we can simply ignore the '5' and solve for 'm':

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3 0
3 years ago
Which expression is equivalent to
Scilla [17]

The equivalent expression of \frac{(5ab)^3}{30ab^{-7}} is \frac{25a^{2}b^{10}}{6}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{(5ab)^3}{30ab^{-7}}

Expand the numerator

\frac{(5ab)^3}{30ab^{-7}} =\frac{125a^3b^3}{30ab^{-7}}

Divide 125 and 30 by 5

\frac{(5ab)^3}{30ab^{-7}} =\frac{25a^3b^3}{6ab^{-7}}

Apply the law of indices

\frac{(5ab)^3}{30ab^{-7}} =\frac{25a^{3-1}b^{3+7}}{6}

Evaluate the exponent

\frac{(5ab)^3}{30ab^{-7}} =\frac{25a^{2}b^{10}}{6}

Hence, the equivalent expression of \frac{(5ab)^3}{30ab^{-7}} is \frac{25a^{2}b^{10}}{6}

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

6 0
3 years ago
Find A if B = 50° and α + β = 100°
goldenfox [79]

Answer:

A=30

Step-by-step explanation:

We know through the Angle Sum Property of A Triangle that

all its angles add up to 180 degrees

Hence, A + (a+b) +B= 180

A+100+50=180

A+150=180

A=30

5 0
3 years ago
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