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3 years ago

Which types of numbers does scientific notation best describe?

1 answer:

4 0

The correct answer is
c) very small and very large

Let's see this with a few examples:
1) if we have a very small number, such as
 $0.0000000001$
we see that we can write it easily by using the scientific notation:
 $1\cdot 10^{-10}$
2) Similarly, if we have a very large number:
 $10000000000$
we see that we can write it easily by using again the scientific notation:
 $1 \cdot 10^{10}$

You might be interested in

An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e

timama [110]

Answer:

K = 80.75 MeV

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

The proton mass is equal to the antiproton mass, so:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0

3 years ago

Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the

Murljashka [212]

Answer:

The net force on the box is 2 N to the left.

The box will move to the left.

The acceleration on the box is 0.5 m/s^2 to the left.

Explanation:

Let's say movement to the right is positive and left is negative.

Bob: +10 N

John: -12 N

Add those together and you get a net force of -2 N, and the negative sign means that the box is moving to the left.

For the acceleration:

Fnet = ma

-2 = (4 kg)a

a = -0.5 m/s^2

Again, the negative sign in this answer means the box is being accelerated to the left.

4 0

4 years ago

Without effective assessment methods, teachers have no documented proof of childrens specific ____ and _____.

schepotkina [342]

Answer:

D strengths and weakneses

Explanation:

8 0

4 years ago

A 1300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/s in precisely oppositedirections participate in a head-on crash.

miskamm [114]

Given

Car 1

m1 = 1300 kg

v1 = 20 m/s

m2 = 900 kg

v2 = -15 m/s

(Negative sign shows that direction of car 2 is opposite to car 1)

Procedure

As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,

$\begin{gathered} m_1v_1+m_2v_2=(m_1+m_2)v \\ v=\frac{m_1v_1+m_2v_2}{m_1+m_2} \\ v=\frac{1300\operatorname{kg}\cdot20m/s-900\operatorname{kg}\cdot15m/s}{1300\operatorname{kg}+900\operatorname{kg}} \\ v=5.681m/s \end{gathered}$

Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.

5 0

1 year ago

1. explain why mid-sized cars and SUVs have different rollover fatality rates.

iris [78.8K]

Answer:

1. They generally have poorer fuel efficiency and require more resources to manufacture than smaller vehicles, thus contributing more to climate change and environmental degradation. Their higher center of gravity increases their risk of rollovers.

2. Mid-sized cars and SUVs both have a fixed object fatality rate of 2.6/BVM. This is most likely because they have a similar mass and inertia. The force of the crash is likely to have about the same deceleration in both vehicles.

Explanation:

brainliest please

8 0

3 years ago