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VikaD [51]
3 years ago
14

Consider a cloudless day on which the sun shines down across the United States. If 2073 kJ of energy reaches a square meter ( m

2 ) of the United States in one hour, how much total solar energy reaches the entire United States per hour
Physics
1 answer:
Mnenie [13.5K]3 years ago
5 0

The total amount of energy per hour is 2.039\cdot 10^{16} kJ

Explanation:

In this problem we are told that the amount of energy reaching a square meter in the United States per hour is

E_1 = 2073 kJ

The total surface area of the United States is

A=9.834\cdot 10^6 km^2

And converting into squared metres,

A=9.834\cdot 10^6 \cdot 10^6 = 9.834\cdot 10^{12} m^2

Therefore, the total energy reaching the entire United States per hour is given by:

E=AE_1 = (9.834\cdot 10^{12})(2073)=2.039\cdot 10^{16} kJ

Learn more about energy and power:

brainly.com/question/7956557

#LearnwithBrainly

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Answer:

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Explanation:

The final plane's vector velocity will be the result of the vector addition of one pointing North of length 300 km/h, another one pointing West of length 50 km/h.

To find the magnitude of the final velocity vector (speed) we need to apply the Pythagorean theorem in a right angle triangle with sides: 300 and 50, and find its hypotenuse:

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and it points 9.46^o West of the North direction.

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