Answer:
As evolutionary biologists have shown, this multicellularity was linked to the rise in oxygen and thus played a significant role for life on Earth as it is today. ... By producing oxygen and evolving into multicellular forms, they played a key role in the emergence of organisms that breathe oxygen.
Explanation:
No two electrons can have the same set of quantum numbers .
<h3>What is Wolfgang Pauli hypothesized an exclusion principle?</h3>
Pauli made a significant advance when he proposed the notion of adding a fourth quantum number to the three that were previously used to represent the quantum state of an electron. Physically speaking, the first three quantum numbers made sense since they had to do with how the electron moved about the nucleus.
The following rule was developed by Austrian physicist Wolfgang Pauli. The quantum numbers of any two electrons cannot be identical.
To put it another way, no two electrons can be in the same state. The Pauli exclusion principle is the name given to this proposition since it forbids electrons from being in the same state.
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Answer:
Explanation:
Kinematics equation for first Object:
but:
The initial velocity is zero
it reach the water at in instant, t1, y(t)=0:
Kinematics equation for the second Object:
The initial velocity is zero
but:
it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s
The velocity is negative, because the object is thrown downwards
Answer:
12 cm and 0.4
Explanation:
f = - 20 cm, u = - 30 cm
Let v be the position of image and m be the magnification.
Use lens equation
1 / f = 1 / v - 1 / u
- 1 / 20 = 1 / v + 1 / 30
1 / v = - 5 / 60
v = - 12 cm
m = v / u = - 12 / (-30) = 0.4
Answer:
18,850 Hz
Explanation:
We need to figure out the wavelength of the sound wave.
Thus,
Wavelength = 1000 * Lowest Amplitude Wave
Wavelength = 1000 * 2.0 * 10^(-5)
Wavelength = 0.02
Or,

Now, we need the frequency of this wave. It goes by the formula:

Where
f is the frequency in Hz
v is the speed of sound in air (to be 377 m/s)
is the wavelength (we found to be 0.02)
Substituting, we find the frequency:

The wave has frequency of 18,850 Hz