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zavuch27 [327]
3 years ago
11

Which of these nebulae is the odd one out?

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0

Answer: The answer is D!

Explanation:

solong [7]3 years ago
3 0

Answer:

Explanation:

A

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Write the difference between convert and<br>Concave minores​
TEA [102]
A concave mirror is opaque whereas a concave lens is transparent. ... Difference between concave mirror and concave lens is A concave mirror is opaque whereas a concave lens is transparent. A concave mirror causes reflection of light whereas a concave lens causes refraction of light.
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2 years ago
In the absence of air resistance, objects fall at constant
Temka [501]

In the absence of air resistance , object fall with  <u>same acceleration</u> .

5 0
3 years ago
I traveled 6.00 km to school in 0.250 hours . What was my average speed
SOVA2 [1]

Answer: 6.67 m/s

Explanation:

Recall that average speed is the total distance covered by a moving body divided by the total time taken. The SI unit is metres per second.

i.e Average speed = distance/time taken

Given that:

Distance covered = 6.00 km

Convert kilometers to meters

If 1 km = 1000 m

6.00 km = (6.00 x 1000) = 6000m

Time taken to school = 0.250 hours

Convert time in hours to seconds

If 1 hour = 60 minutes & 1 minute = 60 seconds

Then, 0.250 hours = (0.250 x 60 x 60)

= 900 seconds

Average speed = ?

Average speed = 6000m/900s

= 6.67 m/s

Thus, your average speed to school is 6.67 m/s

5 0
3 years ago
A particle, mass 0.25 kg is at a position () m, has a velocity () m/s, and is subject to a force () N. What is the magnitude of
NeX [460]
<h2>Question </h2>

A particle, mass 0.25 kg is at a position (<em>-7i + 7j + 5k</em>) m, has a velocity (<em>6i - j + 4k</em>) m/s, and is subject to a force (<em>-5i + 0j - k</em>) N. What is the magnitude of the torque on the particle about the origin?

<h2>Answer:</h2>

47.94Nm

<h2>Explanation:</h2>

The torque (τ) on a particle subject to a force (represented as force vector F) at a position (represented as position vector r) about the origin is given by the cross product of the position vector r for the point of application of a force and the force F. i.e

τ = r x F

Given:

r = (-7i + 7j + 5k) m

F = (-5i + 0j - k) N

                    |   i             j              k    |

r x F  =         |   -7            7              5  |

                    |  -5           0              -1   |

r x F  =       i(-7 - 0) - j(7+25) + k(0+35)

r x F  =       i(-7) - j(32) + k(35)

r x F  =       -7i - 32j + 35k

Therefore the torque τ = -7i - 32j + 35k

The magnitude of the torque is therefore;

|τ| = \sqrt{(-7)^2 + (-32)^2 + (35)^2}

|τ| = \sqrt{49 + 1024 + 1225}

|τ| = \sqrt{2298}

|τ| = 47.94Nm

The magnitude of the torque on the particle about the origin is 47.94Nm

8 0
3 years ago
Find the efficiency of a machine that does 800 J of work if the<br> input work is 2,000 J.
torisob [31]

Answer:

Efficiency: 0.4 (40%)

Explanation:

The efficiency of a simple machine is given by the ratio

\eta = \frac{W_{out}}{W_{in}}

where

W_{in} is the input work of the machine

W_{out} is the output work of the machine

For the machine in this problem, we have:

W_{out}=800 J is the output work

W_{in}=2000 J is the input work

Therefore, the efficiency of the machine is

\eta=\frac{800}{2000}=0.4

Which can be also written as percentage:

\eta=0.4\cdot 100 = 40\%

3 0
3 years ago
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