A concave mirror is opaque whereas a concave lens is transparent. ... Difference between concave mirror and concave lens is A concave mirror is opaque whereas a concave lens is transparent. A concave mirror causes reflection of light whereas a concave lens causes refraction of light.
In the absence of air resistance , object fall with <u>same acceleration</u> .
Answer: 6.67 m/s
Explanation:
Recall that average speed is the total distance covered by a moving body divided by the total time taken. The SI unit is metres per second.
i.e Average speed = distance/time taken
Given that:
Distance covered = 6.00 km
Convert kilometers to meters
If 1 km = 1000 m
6.00 km = (6.00 x 1000) = 6000m
Time taken to school = 0.250 hours
Convert time in hours to seconds
If 1 hour = 60 minutes & 1 minute = 60 seconds
Then, 0.250 hours = (0.250 x 60 x 60)
= 900 seconds
Average speed = ?
Average speed = 6000m/900s
= 6.67 m/s
Thus, your average speed to school is 6.67 m/s
<h2>
Question
</h2>
A particle, mass 0.25 kg is at a position (<em>-7i + 7j + 5k</em>) m, has a velocity (<em>6i - j + 4k</em>) m/s, and is subject to a force (<em>-5i + 0j - k</em>) N. What is the magnitude of the torque on the particle about the origin?
<h2>
Answer:</h2>
47.94Nm
<h2>
Explanation:</h2>
The torque (τ) on a particle subject to a force (represented as force vector F) at a position (represented as position vector r) about the origin is given by the cross product of the position vector r for the point of application of a force and the force F. i.e
τ = r x F
Given:
r = (-7i + 7j + 5k) m
F = (-5i + 0j - k) N
| i j k |
r x F = | -7 7 5 |
| -5 0 -1 |
r x F = i(-7 - 0) - j(7+25) + k(0+35)
r x F = i(-7) - j(32) + k(35)
r x F = -7i - 32j + 35k
Therefore the torque τ = -7i - 32j + 35k
The magnitude of the torque is therefore;
|τ| = 
|τ| = 
|τ| = 
|τ| = 47.94Nm
The magnitude of the torque on the particle about the origin is 47.94Nm
Answer:
Efficiency: 0.4 (40%)
Explanation:
The efficiency of a simple machine is given by the ratio

where
is the input work of the machine
is the output work of the machine
For the machine in this problem, we have:
is the output work
is the input work
Therefore, the efficiency of the machine is

Which can be also written as percentage:
