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stealth61 [152]
3 years ago
6

52.45 x 4.78 \ What is the value of the expression?

Mathematics
2 answers:
dangina [55]3 years ago
8 0
I think the answer is 250.711
Tpy6a [65]3 years ago
7 0

Answer:

250.711

Step-by-step explanation:

You just multiply my dude.

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The sum of three numbers is 52. The third number is 2 times the first. The second number is 8 less than the first. What are the
Lena [83]

Answer:

3rd number = 30

2nd number = 7

1st number = 15

Step-by-step explanation:

(T) total of three numbers = 52

let 3rd number = 2 x

let 2nd number = x - 8

let 1st number = x

T = 1st + 2nd + 3rd

52 = 2x + (x - 8) + x

52 + 8 = 4x

60 = 4x

x = 60 / 4

x = 15

therefore,

let 3rd number = 2 (15) = 30

let 2nd number = 15 - 8 = 7

let 1st number = 15

4 0
3 years ago
Read 2 more answers
DOES the given value make the inequalities true? x + 9 > 21, when x = 15?
Kobotan [32]

Answer:

Yes.

Step-by-step explanation:

When x=15,

x+9=15+9=24 > 21.

7 0
3 years ago
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Thr four angles of a quadrilateral L are in the ratio 5:2:3:8find the angle
Anuta_ua [19.1K]
Ratio = 5:2:3:8
Sum of all internal angles = 360°
5x + 2x + 3x + 8x = 360°
18x = 360°
x = 20°
Therefore,
5x = 100°
2x = 40°
3x = 60°
8x = 160°
5:2:3:8 :: 100:40:60:160.
5 0
3 years ago
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Simplify, Write your answer in exponential notation.<br> a.) 2³ x 2-5<br> b.) (602)3
mariarad [96]

The simplified expressions are 2^-2 and 60^6

<h3>How to simplify the expressions?</h3>

<u>Expression (a)</u>

We have:

2^3 * 2^-5

Apply the product law of indices

2^3 * 2^-5 = 2^(3 - 5)

Evaluate the difference

2^3 * 2^-5 = 2^-2

<u>Expression (b)</u>

We have:

(60^2)^3

Apply the power law of indices

(60^2)^3 = 60^(2 * 3)

Evaluate the product

(60^2)^3 = 60^6

Hence, the simplified expressions are 2^-2 and 60^6

Read more about expressions at:

brainly.com/question/723406

#SPJ1

8 0
2 years ago
Find the value of the expression: a. 3x^0 for x=2.6, b. 10a^2b^0 for a=–3, b=–8
nekit [7.7K]

Step-by-step explanation:

For x = 2,6

= 3{x}^{0}

= 3 \times {2,6}^{0}

= 3 \times1

= 3

\:

For a = -3 and b = -8

= 10  \times {a}^{2}  \times {b}^{0}

= 10 \times  {( - 3)}^{2}  \times  {( - 8)}^{0}

= 10 \times 9 \times 1

= 90

3 0
3 years ago
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