Answer:
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Explanation:
While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.
- The object with the greater mass exerts a more gravitational force on the other object.
We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Answer: <span>Protons do not move out of the nucleus of atoms although they repel each other.
Reasoning:
Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.
That repulsion force tends to destabilize the atom. The only reason why the atom does not explode is because there is a there exists a force of attraction that exceeds the repulsion of the like charged protons. That is the strong nuclear force. Therefore, the strong nuclear forces are stronger than the electromagnetic force that tends to get the protons apart.
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Grassland is the most likely have the deepest layer of topsoil
Topsoil is the outermost layer of the soil that has the highest concentration of of organic matter and microorganism which is very important for plant's growth. Since grassland have a deep layers of topsoil, most of the farmers us it to grow their farm products
Answer:
P = 1000000[Pa] = 1000 [kPa]
Explanation:
To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.
where:
P = pressure [Pa] (units of pascals)
F = force = 100 [N]
A = area = 100 [mm²]
But first we must convert the units from square millimeters to square meters.
![A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]](https://tex.z-dn.net/?f=A%3D100%5Bmm%5E%7B2%7D%5D%2A%5Cfrac%7B1%5E%7B2%7D%20m%5E%7B2%7D%20%7D%7B1000%5E%7B2%7Dmm%5E%7B2%7D%20%20%7D%20%3D0.0001%5Bm%5E%7B2%7D%20%5D)
Now replacing:
![P=100/0.0001\\P=1000000[Pa]](https://tex.z-dn.net/?f=P%3D100%2F0.0001%5C%5CP%3D1000000%5BPa%5D)
Answer:
The parametric equation for the position of the particle is 
.
Explanation:
Given that,
The point is
Time t = 3
Velocity 
We need to calculate the parametric equation for the position of the particle
Using parametric equation for position
....(I)
at t = 3,
Put the value into the formula
Put the value of r₀ in equation (I)
Hence, The parametric equation for the position of the particle is .
