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vagabundo [1.1K]
3 years ago
9

The gymnast has a mass of 45 kg gravitational field strength = 9.8 N/kg - Calculate the weight of the gymnast. Use the equation:

weight = mass x gravitational field strength =
Weight =
​
Physics
1 answer:
tia_tia [17]3 years ago
7 0

Answer: B. The gravitational field strength of Planet X is Wx/m.

Explanation:

Weight is a force, and as we know by the second Newton's law:

F = m*a

Force equals mass times acceleration.

Then if the weight is:

Wx, and the mass is m, we have the equation:

Wx = m*a

Where in this case, a is the gravitational field strength.

Then, isolating a in that equation we get:

Wx/m = a

Then the correct option is:

B. The gravitational field strength of Planet X is Wx/m.

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A piece of glass has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavele
Usimov [2.4K]

Answer:

200 nm

Explanation:

Refractive index of gasoline = 1.4

Wavelength = 560 nm

t = Thickness of film

m = Order = 1

Wavelength is given by

\lambda=\dfrac{560}{1.4}=400\ nm

We have the relation

2t=m\lambda\\\Rightarrow t=\dfrac{m\lambda}{2}\\\Rightarrow t=\dfrac{1\times 400}{2}\\\Rightarrow t=200\ nm

The thickness of the film is 200 nm

4 0
3 years ago
Learning Check: Ranking Elements
loris [4]
Yes
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8 0
3 years ago
Which would you expect to find in a home with passive solar heating?
tatyana61 [14]

A lot of windows, skylights, and open floor areas.

6 0
3 years ago
A Go Kart (m = 35 kg) has a top speed of 12 m/s . A student traveling at top speed locks the brake to avoid hitting a bus after
Sergeu [11.5K]

Answer:

350 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of Go Kart = 35 kg

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Force (F) =?

Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Final velocity (v) = 0 m/s

Acceleration (a) =.?

v² = u² + 2as

0² = 12² + (2 × a × 7.2)

0 = 144 + 14.4a

Collect like terms

0 – 144 = 14.4a

– 144 = 14.4a

Divide both side by 14.4

a = – 144 / 14.4

a = – 10 m/s²

The negative sign indicate that the Go Kart is decelerating when the brake was applied.

Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:

Mass (m) of Go Kart = 35 kg

Acceleration (a) = 10 m/s

Force (F) =?

F = ma

F = 35 × 10

F = 350 N

Thus, the Go Kart has a force of 350 N when the student locked the brake.

7 0
3 years ago
A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
dybincka [34]

Answer:

Explanation:

Given

Force=18lb

extension=8in

Using Hooke's law to get the spring constant(k)

F=ke

Then,

K=f/e

K=18/8

K=2.25lb/in

Work done by spring is given by

W=1/2Fe

Or W=1/2ke²

Then,

Work done in stretching the spring to 14in

W=1/2ke²

W=0.5×2.25×14²

W=220.5lbin

1 Inch-pounds Force to Joules = 0.113J

Then, to joules

W=0.133×220.5

W=29.33J

5 0
4 years ago
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