Question

A distributor claims that the chance that any of the three major components of a computer (CPU, monitor, and keyboard) is defective is 3%. Calculate the chance that no more than one component is defected in a computer set.

Answer 1

Answer: 94.09%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^{n-x}$, where P(x) is the probability of getting success in x trials , n is number of trials and p is the probability of getting success in each trial.

Given : The probability that the any of the three major components of a computer is defective =0.03

Now, the probability that no more than one component is defected in a computer set :-

$P(x\leq1)=P(0)+P(1)\\\\=^3C_0(0.03)^0(0.97)^3+^3C_1(0.03)^1(0.97)^2\\\\=(0.97)^3+(0.03)^1(0.97)^2=0.9409=94.09\%$

Hence, the chance that no more than one component is defected in a computer set is 94.09% .